Graphing electric potential for two positive charges

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Homework Statement
Please see below
Relevant Equations
Please see below
For part (a) of this problem,
Diagram of two charged particles of charge Q on the y axis, one a distance a above and one a distance a below the x axis, labeled Figure P24.14, with the problem text beside it.

The solution is
Worked solution for the electric potential of two equal positive charges on the x axis, ending in V(x)/(k_eQ/a) = 2/sqrt((x/a)^2 + 1), beside a plot of that function from x/a = -4 to 4, peaking at about 2.0 at x/a = 0.

However, my solution is
Hand-drawn graph of electric potential V against x in metres, with V marked in units of k_eQ/a on the vertical axis; an orange curve peaks at x = 0 and falls off symmetrically, with points labelled -3a, -2a, -a, a, 2a and 3a on the horizontal axis.

Am I correct? In the solutions that don't appear to plot the electric potential as units of ## \frac {k_eQ} {a} ## like I have which the problem statement said to do.

Many thanks!
 
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Your plot is too crudely drawn for a direct comparison with the textbook. Not only that, but in your plot the tick marks on the vertical axis are not equally spaced as is the case in the textbook plot. So what exactly are you comparing? I suggest that you use a plotting program instead of doing it freehand. Free plotting programs exist on the internet. I went to https://www.desmos.com/calculator and created this.

Graph of a smooth bell-shaped curve on a grid, peaking at 2 at x = 0 and falling toward about 0.8 at x = -4 and x = 4, with axis labels -4, -2, 0, 2, 4 and -2, 2.
 
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kuruman said:
Your plot is too crudely drawn for a direct comparison with the textbook. Not only that, but in your plot the tick marks on the vertical axis are not equally spaced as is the case in the textbook plot. So what exactly are you comparing? I suggest that you use a plotting program instead of doing it freehand. Free plotting programs exist on the internet. I went to https://www.desmos.com/calculator and created this.

View attachment 321043
Yes sorry @kuruman I will graph it. I am comparing my graph which has a y-axis of ## V(\frac{k_eQ}{a}) = \frac {2}{\sqrt{10}}, \frac {2}{\sqrt{5}}, \frac {2}{\sqrt{2}}, 2## and x-axis of## x(a) = -3a, -2a, -a, a, 2a, 3a ##
 
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kuruman said:
Your plot is too crudely drawn for a direct comparison with the textbook. Not only that, but in your plot the tick marks on the vertical axis are not equally spaced as is the case in the textbook plot. So what exactly are you comparing? I suggest that you use a plotting program instead of doing it freehand. Free plotting programs exist on the internet. I went to https://www.desmos.com/calculator and created this.

View attachment 321043
Here is my new graph @kuruman
Graph of V in units of k_e Q / a against x, symmetric about x = 0, peaking at 2 at the origin and decaying toward zero on both sides; marked at x = -3a, -2a, -a, a, 2a, 3a and at heights 2/√2, 2/√5, 2/√10.

I am comparing the y and x axes. I am not sure whether my graph is correct or not.

Thanks!
 
Attachments
  • Graph of V(k_eQ/a) against x(a), a symmetric red curve peaking at 2 at x = 0 and decaying toward both sides, with labelled ticks at ±a, ±2a, ±3a and values 2/√2, 2/√5, 2/√10 on the vertical axis.
    1674598616983.png
    18.9 KB · Views: 180
It is not correct. The x-axis is fine and compares directly with the textbook and my plot if ##a=1##, i.e. plot ##k_eQ/ a## vs. ##x/a##. The y-axis is not OK. You cannot label equally spaced intervals using unequal labels. Since there are four intervals between zero and 2 on the vertical axis, the labels should be 0.5, 1.0 and 1.5. In fact the demos plotting utility assumes that this is the case.
 
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kuruman said:
It is not correct. The x-axis is fine and compares directly with the textbook and my plot if ##a=1##, i.e. plot ##k_eQ/ a## vs. ##x/a##. The y-axis is not OK. You cannot label equally spaced intervals using unequal labels. Since there are four intervals between zero and 2 on the vertical axis, the labels should be 0.5, 1.0 and 1.5. In fact the demos plotting utility assumes that this is the case.
Thank you for your reply @kuruman ! Whoops I see my mistake with the y-axis. Also, I've never seen the notation ##x/a## - what does it mean please?

I will post a new graph soon.
 
kuruman said:
It is not correct. The x-axis is fine and compares directly with the textbook and my plot if ##a=1##, i.e. plot ##k_eQ/ a## vs. ##x/a##. The y-axis is not OK. You cannot label equally spaced intervals using unequal labels. Since there are four intervals between zero and 2 on the vertical axis, the labels should be 0.5, 1.0 and 1.5. In fact the demos plotting utility assumes that this is the case.
Here's the new graph @kuruman ,
Graph of V(k_eQ/a) against x from -3a to 3a, a symmetric red curve peaking at 2 at x = 0 and falling toward 0.5 at the ends.
 
That's fine except for the old labels on the vertical axis that need to be removed. Just so that you know. You don't have to do it because it's not going to be graded.
 
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kuruman said:
That's fine except for the old labels on the vertical axis that need to be removed. Just so that you know. You don't have to do it because it's not going to be graded.
Thank you @kuruman , but I still don't see how my and their graphs are equivalent. On their graph the y-axis is ## \frac {V(x)a} {k_eQ}## and my graph it is ## V (\frac {k_eQ} {a}) ##

For the x-axis, their graph is ## x/a ## and my graph is ## x ##.

Correct me if I am wrong, but the notation ## x ## is the same as ## x(a) ##. I'm not sure why.

Many thanks!
 
Callumnc1 said:
Thank you @kuruman , but I still don't see how my and their graphs are equivalent. On their graph the y-axis is ## \frac {V(x)a} {k_eQ}## and my graph it is ## V (\frac {k_eQ} {a}) ##

For the x-axis, their graph is ## x/a ## and my graph is ## x ##.

Correct me if I am wrong, but the notation ## x ## is the same as ## x(a) ##. I'm not sure why.

Many thanks!
EDIT: Sorry I meant that the notation ## x ## is not the same as ## x(a) ##
 
This may help https://www.desmos.com/calculator/zu8hbssbxp . (Visit to see how the pieces below are created.)

Vary the a-slider.

(By the way, you can copy-paste equations from desmos (as TeX, acceptable for MathJax)... just surround by itex and /itex in square brackets .)

[itex]V_{factor}=\frac{2}{\sqrt{\left(x_{factor}\right)^{2}+1}}[/itex] (right-click the equation)
where
[itex]V=\frac{kQ}{a}\left(\frac{2}{\sqrt{\left(\frac{x}{a}\right)^{2}+1}}\right)[/itex]

[itex]V_{fac}=\frac{V}{\left(\frac{kQ}{a}\right)}[/itex] and [itex]x_{fac}=\frac{x}{a}[/itex] (different variable names given in Desmos) are both dimensionless quantities.
([itex]\frac{kQ}{a}[/itex] carries the units of Volts, and [itex]\frac{x}{a}[/itex] carries the units of meters.)Note that if the [implied] right-hand-side of an entry has a free variable, it becomes the independent variable.

Graph of V(x)/(kQ/a) against x/a, a bell-shaped curve peaking at 2 at x=0 and decaying toward zero on both sides, with labelled points (1, 1.414), (2, 0.894) and (3, 0.632) and magenta dots tracing the curve.
 
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robphy said:
This may help https://www.desmos.com/calculator/zu8hbssbxp . (Visit to see how the pieces below are created.)

Vary the a-slider.

(By the way, you can copy-paste equations from desmos (as TeX, acceptable for MathJax)... just surround by itex and /itex in square brackets .)

[itex]V_{factor}=\frac{2}{\sqrt{\left(x_{factor}\right)^{2}+1}}[/itex] (right-click the equation)
where
[itex]V=\frac{kQ}{a}\left(\frac{2}{\sqrt{\left(\frac{x}{a}\right)^{2}+1}}\right)[/itex]

[itex]V_{fac}=\frac{V}{\left(\frac{kQ}{a}\right)}[/itex] and [itex]x_{fac}=\frac{x}{a}[/itex] (different variable names given in Desmos) are both dimensionless quantities.
([itex]\frac{kQ}{a}[/itex] carries the units of Volts, and [itex]\frac{x}{a}[/itex] carries the units of meters.)Note that if the [implied] right-hand-side of an entry has a free variable, it becomes the independent variable.

View attachment 321094
Thank you for your reply @robphy ! I kind of get what you are saying that my and their graphs are equivalent, is that correct?

Many thanks!
 
robphy said:
Type in your equation in that Desmos file and see if it matches.
Thank you for your reply @robphy! How do I do that sorry?

Many thanks!
 
On that Desmos file, add a blank entry or scroll down to find one blank entry.
Type in your formula, using variable names not already used.
 
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robphy said:
On that Desmos file, add a blank entry or scroll down to find one blank entry.
Type in your formula, using variable names not already used.
Thank you @robphy! I will give it a try and post it.
 
robphy said:
On that Desmos file, add a blank entry or scroll down to find one blank entry.
Type in your formula, using variable names not already used.
Thanks @robphy - it seems to be working! However why dose it work?

Many thanks!