Grassmann variables and Weyl spinors

302021895
Messages
8
Reaction score
0
I just started studying supersymmetry, but I am a little bit confused with the superspace and superfield formalism. When expanding the vector superfield in components, one obtains therms of the form \theta^{\alpha}\chi_{\alpha}, where \theta is a Grassmann number and \chi is a Weyl vector.

I am aware that Grassmann numbers anticommute \{\theta_{\alpha},\theta_{\beta}\}=0, and that ordinary numbers commute with Grassmann variables. Do Weyl spinor components commute or anticommute with the Grassmann variables? (\{\theta_{\alpha},\chi_{\beta}\}=0 or [\theta_{\alpha},\chi_{\beta}]=0).
 
Physics news on Phys.org
Weyl spinor components are Grassman variables. As such they anticommute with other Grassman variables.

I'm not sure why you call the chi a "Weyl vector". The vector superfield V is not a vector, but it describes a vector multiplet and as such contains a field v_{\mu} which is a spacetime vector.
 
Hi!
I have a similar problem: what is the result of a commutator/anticommutator like this?
\left\{ \left( \gamma^{\mu} \theta \right)_{\alpha} \partial_{\mu} , \frac{\partial}{\partial \bar{\theta}^{\beta} } \right\}
Thank you
 
Use that the theta's (both the parameters and derivatives wrt them) anticommute and form an orthogonal basis for the fermionic part of superspace.
 
I seem to notice a buildup of papers like this: Detecting single gravitons with quantum sensing. (OK, old one.) Toward graviton detection via photon-graviton quantum state conversion Is this akin to “we’re soon gonna put string theory to the test”, or are these legit? Mind, I’m not expecting anyone to read the papers and explain them to me, but if one of you educated people already have an opinion I’d like to hear it. If not please ignore me. EDIT: I strongly suspect it’s bunk but...
Back
Top