- #1
brad sue
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Hi I am stuck with this problem:
A deep hole in Earth reaches a depth of one half of Earth's radius. How much work is done when a 1-kg mass is slowly lifted from the bottom of the hole to Earth's surface?
I use the expression of the gravitation force, F=GMm/R3
so the work would be:
integral (F*(R/2)) from R=R/2 to R=R
I am not sure I am right so I need your input please.
Thank you
Brad
A deep hole in Earth reaches a depth of one half of Earth's radius. How much work is done when a 1-kg mass is slowly lifted from the bottom of the hole to Earth's surface?
I use the expression of the gravitation force, F=GMm/R3
so the work would be:
integral (F*(R/2)) from R=R/2 to R=R
I am not sure I am right so I need your input please.
Thank you
Brad