Gravitation problem about throwing an object upward

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SUMMARY

The discussion focuses on calculating the maximum height a rock reaches when thrown upward from a small moon with a radius of 6.00 x 104 m and mass of 7.50 x 1018 kg. The astronaut throws the rock with an initial speed of 38.5 m/s. The incorrect application of kinematic equations was identified, as they assume a constant gravitational acceleration, which is not valid for this scenario. Instead, a conservation of energy approach should be utilized, incorporating gravitational potential energy as a function of radial distance.

PREREQUISITES
  • Understanding of gravitational force and the formula g = GM/r2
  • Familiarity with kinematic equations for projectile motion
  • Knowledge of conservation of energy principles in physics
  • Basic understanding of gravitational potential energy
NEXT STEPS
  • Study the conservation of energy in gravitational fields
  • Learn how to derive gravitational potential energy as a function of radial distance
  • Explore the differences between kinematic equations on Earth and in varying gravitational fields
  • Practice problems involving projectile motion on celestial bodies with different masses and radii
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Students studying physics, particularly those focusing on mechanics and gravitational effects, as well as educators looking for examples of conservation of energy in non-Earth environments.

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Homework Statement


Standing on the surface of a small spherical moon whose radius is 6.00*104 m and whose mass is 7.50*1018 kg, an astronaut throws a rock of mass 2.05 kg straight upward with an initial speed 38.5 m/s. (This moon is too small to have an atmosphere.) What maximum height above the surface of the moon will the rock reach?


Homework Equations



g=GM/r2

The Attempt at a Solution


I calculated g, then used the kinematic equation Δy = (vf2 - vi2) / 2a, but it didn't work! Did I use the wrong equations?
 
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xnitexlitex said:

Homework Statement


Standing on the surface of a small spherical moon whose radius is 6.00*104 m and whose mass is 7.50*1018 kg, an astronaut throws a rock of mass 2.05 kg straight upward with an initial speed 38.5 m/s. (This moon is too small to have an atmosphere.) What maximum height above the surface of the moon will the rock reach?


Homework Equations



g=GM/r2

The Attempt at a Solution


I calculated g, then used the kinematic equation Δy = (vf2 - vi2) / 2a, but it didn't work! Did I use the wrong equations?

Yup. The kinematic equations involving g that we use near the surface of the Earth are valid when g remains essentially constant over the trajectory of the projectile. This holds because the relative change in the radial distance from the center of the Earth is negligible, and g = G*M/r.

For your moon, the radius is relatively small and the upward launch speed will take the projectile a distance that is not negligible with respect to that radius.

You would be better to use a conservation of energy approach, using the appropriate expression for the gravitational potential energy as a function of radial distance.
 

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