Gravitation with Conservation of Energy and Momentum

AI Thread Summary
Two spheres with masses M and 2M are released from a distance of 12R, and the discussion focuses on finding their collision speeds using conservation of energy and momentum. The gravitational potential energy equation is correctly identified as U = (G*M1*M2)/R, and the initial and final energy states are set up for analysis. The challenge arises in expressing the velocity of the smaller sphere (v1) in terms of the larger sphere's velocity (v2) without including the radius R in the final answer. Participants emphasize the importance of recognizing initial velocities as zero and correctly applying conservation principles to derive the necessary relationships. The conversation highlights the complexities of solving for v1 and v2 while ensuring all variables are accounted for.
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1. Two spheres having masses M and 2M and radii R and 3R, respectively, are simultaneously released from rest when the distance between their centers is 12R. Assume the two spheres interact only with each other and we wish to find the speeds with which they collide. Write an equation from one of the models and solve it for v1, the velocity of the sphere of mass M at any time after release in terms of v2, the velocity of 2M.

2. Homework Equations :

Fg = Gm1m2/r^2

E = K + U

p=mv

3. Do I just use conservation of energy?

Ei = 0 + [G(M)(2M)]/(R^2)

Ef = 1/2Mv1^2 + 1/2(2M)v2^2 + 0

change in E = [1/2Mv1^2 + 1/2(2M)v2^2] - [G(M)(2M)]/(R^2)
This equals 0 since there are no nonconservation forces doing work.
change in E= Wnc = 0

My answer is sqrt(M/36R - 2v2^2) not correct

This is confusing me because it asks for v1 in terms of v2 and I have R in the answer. How do I solve it without R?

I also have to solve this using conservation of momentum.

Mv1i+2Mv2i = Mv1f + 2Mv2f

I don't get how to solve this for v1 in terms of v2 when I don't know initial or final velocities.
 
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blackheart said:
Fg = Gm1m2/r^2

E = K + U

p=mv

3. Do I just use conservation of energy?

Ei = 0 + [G(M)(2M)]/(R^2)

Ef = 1/2Mv1^2 + 1/2(2M)v2^2 + 0

If you are using conservation of energy to solve this problem, the relevant equation for gravitational potential energy should be U=(G*M1*M2)/R

the R does not have a power 2.

use this to formulate an equation for the U(initial) and U(final).
 
blackheart said:
I also have to solve this using conservation of momentum.

Mv1i+2Mv2i = Mv1f + 2Mv2f

I don't get how to solve this for v1 in terms of v2 when I don't know initial or final velocities.

You do know the initial velocities:

'1. Two spheres having masses M and 2M and radii R and 3R, respectively, are simultaneously released from rest.'

ehild
 
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