Gravitational and elastic energy

AI Thread Summary
To determine the necessary length of the spring and mass combined (y) so that the mass just touches the floor, the equations for elastic energy (Ee = kx²/2) and gravitational energy (Eg = mgh) are utilized. The equilibrium length of the spring is h2, and the total height from the floor to the ceiling is h1. The relationship h1 = h2 + x + y is established, where x represents the extension of the spring. By substituting the value of x into the equations and solving, the required length y can be calculated. The solution provides insight into the balance of gravitational and elastic forces in this system.
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Homework Statement



A spring with spring constant k is hanging from the ceiling, at equilibrium point. The length of the spring in equilibrium is h2. Then you hang a mass less string from the end of the spring, holding a mass m. The length of the string and the mass together equal y.
The height of the floor to the ceiling is h1

Using elastic and gravitational energy equations, what is the necessary length of the spring and the mass combined (y), so that when you hang the mass, it just touches the floor? (in other words, solve for y?)

Homework Equations



Ee=kx2/2

Eg=mgh
 
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If x is the extension in the spring, then
h1 = h2 + x + y.
Substitute the value of x, in the relevant equations and solve for y.
 
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