Gravitational Field Problem - Integrate?

AI Thread Summary
The discussion focuses on calculating the gravitational field produced by a nonuniform thin rod on the x-axis at a point x0 greater than L. The mass per unit length of the rod varies as λ = Cx, leading to the expression for gravitational force as Gλdx/(x0 - x)². Participants clarify that the correct denominator should be (x0 - x)², reflecting the distance from the mass element to the point of interest. The original poster expresses confusion about integrating the variable dx but later acknowledges their misunderstanding. The thread emphasizes the importance of proper integration limits and understanding calculus concepts in solving the problem.
Mmm_Pasta
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Homework Statement


A nonuniform thin rod of length L lies on the x axis. One end of the rod is at the origin, and the other end is at x = L. The rod's mass per unit length λ varies as λ = Cx, where C is a constant. (Thus, an element of the rod has mass dm = λdx.)

Determine the gravitational field due to the rod on the x-axis at x = x0, where x0 > L. (Use the following as necessary: G, M, L, x0.)

Homework Equations



F=GMm/d^2
g=GM/d^2

The Attempt at a Solution


Since the mass varies depending what L is, the equation would be Gdm/(x0-L)^2 which is Gλdx/(x0-L)^2. Do I then integrate to get rid of the dx? If I do I am not sure what dx would be to begin with.
 
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Mmm_Pasta said:

The Attempt at a Solution


Since the mass varies depending what L is, the equation would be Gdm/(x0-L)^2 which is Gλdx/(x0-L)^2.

This looks close, although I think it should be (x0 - x)2 in the denominator, since you are talking about the contribution due to the infinitesimal mass element located at position x.

Mmm_Pasta said:
Do I then integrate to get rid of the dx? If I do I am not sure what dx would be to begin with.

What do you mean by "I don't know what the dx would be to begin with?" :confused: Do you know calculus?
 
I put L because x0 is greater than L, but now I know why it is x. Never mind about the dx; I worded the question wrong, but I know now. Thanks. =)
 
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