Gravitational Field Related Question

AI Thread Summary
A satellite must orbit Earth at an altitude where the gravitational field strength is 4.5 N/kg, which corresponds to approximately 3,034,716.6 meters above the surface. To find the acceleration of the satellite, it can be equated to the gravitational field strength, resulting in an acceleration of 4.5 m/s². The velocity required to maintain this orbit can be calculated using the formula v = √(GM/r). The discussion emphasizes that the gravitational field strength directly relates to the acceleration due to gravity. Understanding these relationships is crucial for solving satellite motion problems.
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A satellite is designed to orbit Earth at an altitude above its surface that will place it in a gravitational field with a strength of 4.5 N/kg.

a) Calculate the distance above the surface of Earth at which the satellite must orbit.

b) Assusming the orbit is circular, calculate the acceleration of the satellite and its direction.

c) At what speed must the satellite travel in order to maintain this orbit.

(I already found the answer for a) i got approximately 3034716.6 m above Earth)

For c) I know I can use the equation v = {GmE/r} ( {} = square root)

but i am not sure how to find the acceleration for b). the only thing i can think of is using
ac = v^2/r.

Any suggestions?

Thanks



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The Attempt at a Solution

 
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Yes, it is the centripetal acceleration.
 
but i would have to find the velocity first? in order to find the acceleration, right?
 
Yes, and you know already the expression for the velocity, speed more correctly.
 
alright thank you very much, much appreciated
 
This question can be done in a less roundabout way by writing out Newton's second law for the satellite:

F_net=ma
GMm/r2=ma
a=GM/r2

You'll realize that this is also the gravitational field strength, so acceleration = 4.5 N/kg = 4.5 m/s2. Remember that: gravitational field strength is equal to acceleration due to gravity.
 
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