Gravitational field strength of 0

AI Thread Summary
To find the point where the net gravitational field strength is zero between a planet and its moon, the gravitational forces exerted by both bodies must balance. The equation GMm/r^2 is used to express the gravitational force, where G is the gravitational constant, M is the mass of the planet, m is the mass of the moon, and r is the distance. By setting the gravitational forces equal, the equation GMm/x^2 = GMm/(d-x)^2 can be derived, where d is the distance between the planet and moon. The challenge lies in correctly substituting the values and solving for x, the distance from the planet. This approach will yield the location where the gravitational field strength is zero.
inuyasha555
Messages
1
Reaction score
0

Homework Statement


A planet of mass 1.88x10^21 kg has a moon of mass 4.56^10^19 kg. The distance between their centers is 3.94x10^8 m. How far from the center of the planet (along the line joining the planet and the moon) is the net gravitational field strength, due to the two bodies, equal to 0?

Homework Equations


Fg = GMm/r^2


The Attempt at a Solution



GMm/r^2 - GMm/r^2 = 0.

Somewhere in there I'm thinking I can put in the point (x) but I have no idea where or how to approach this.
 
Physics news on Phys.org
If d is the distance between the planet and the moon, and the x is the distance at which the field is zero from the planet, then the distance from the moon to that point is (d - x).
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top