Gravitational force = 0 between two planets?

AI Thread Summary
The discussion revolves around a physics problem involving gravitational forces between a planet and its moon. An object is positioned between them such that the net gravitational force acting on it is zero. The equation M/d^2 = m/(R-d)^2 is derived to find the distance d from the planet's center. The participants confirm that the approach is correct and suggest solving the resulting quadratic equation to find the value of d. The focus remains on applying gravitational equations to determine the object's position accurately.

Which is the answer?

  • ((M-m)/(M+m))R

    Votes: 0 0.0%
  • (M+m)/(M-m)

    Votes: 0 0.0%
  • (((M^.5)+(m^.5))/(M-m)) * (M^.5) R

    Votes: 0 0.0%
  • (((M-m)/(M+m))^.5) * R

    Votes: 0 0.0%
  • (((M^.5)-(m^.5))/(M-m)) * (M^.5) R

    Votes: 0 0.0%

  • Total voters
    0
  • Poll closed .
Hayden_
Messages
1
Reaction score
0

Homework Statement



A planet of mass M has a moon of mass m in a circular orbit of radius R. An object is placed between the planet and the moon on the line joining the center of the planet to the center of the moon so that the net gravitational force on the object is zero. How far is the object placed from the center of the planet?

Homework Equations



Fg=G(Mm/R^2)

I used the variable d to describe how far the object is placed from the center of the planet

The Attempt at a Solution



G(M(mass of object))/d^2 = G(m(mass of object))/(R-d)^2

G and mass of object cancel out

M/d^2 = m/(R-d)^2
 
Physics news on Phys.org
find d.?
 
Looks good to me!

Hi Hayden! Welcome to PF :smile:

Hayden_ said:
M/d^2 = m/(R-d)^2

Looks good to me!

Now all you have to do is to solve the quadratic equation … :smile:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top