Gravitational Force (Earth and Sun)

AI Thread Summary
The discussion focuses on calculating the required thickness of a steel cable that would replace gravitational force between the Earth and the Sun. The initial calculations provided by the user involve using formulas related to gravitational and circular motion, but the results are deemed incorrect. Key points include the need to relate the maximum tensional force to the cross-sectional area of the cable, emphasizing that centripetal force divided by area must equal the tensile strength of the steel. The user seeks guidance on correcting their approach to arrive at the correct thickness. Understanding the relationship between force, area, and tensile strength is crucial for solving the problem accurately.
jgens
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Homework Statement



To better comprehend the gravitational force between the Earth and the Sun, pretend gravity is turned off and the pull replaced by the tension in a steel cable joining them. How thick would such a cable need to be? You can estimate the diameter by knowing the tensile strength of steel cable is about 5.1 * 10^8 N/m^2.



Homework Equations



Any equations concerning gravitation/cirular motion.

The Attempt at a Solution



This is my attempt at a solution, the answer key says it's wrong.

F = m(4)(pi^2)(r)/t^2

d^2 = m(4)(pi^2)(r)/(t^2)(tensile strength)

thickness = m(4)(pi^2)/(t^2)(tensile strength)

thinkness = 465.45 m or 0.465 km

Where have I gone wrong in my calculations? Can someone please steer me in the right direction. Thanks.
 
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jgens said:
F = m(4)(pi^2)(r)/t^2

OK.

d^2 = m(4)(pi^2)(r)/(t^2)(tensile strength)

Didn't understand.

Try to think simply.

Max tensional force/cross-sectional area of cable = tensile strength =>
Centripetal force/area = tensile strength.
 
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