Gravitational Force: Examining Effects of Distance on Charge

AI Thread Summary
If the electrostatic force between two positively charged objects equals the gravitational force, they would remain in equilibrium at that specific distance. Moving the objects closer would disrupt this balance, causing the stronger electrostatic force to dominate and push them apart. Conversely, moving them further apart would also result in the electrostatic force overpowering the gravitational force. The electrostatic force is significantly stronger, by a factor of trillions, which means any disturbance would lead to a rapid separation of the objects. Overall, the inherent strength of electrostatic forces dictates their behavior in relation to gravitational forces.
LNCO
Messages
1
Reaction score
0

Homework Statement



What would happen if the size of the electrostatic force acting between two positively charged objects was exactly the same as that of the gravitational force acting between them? What would happen if they were moved closer together or further apart?
 
Physics news on Phys.org
You probably mean strength of force. In that case, the 2 forces will cancel each other out at that distance between them and they will stay in equilibrium. However, as electrostatic force is much stronger (in term of trillion times or something) than gravitational force, any disturbance would cause them to fly violently apart.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top