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Homework Statement
i need help with this problem (Online HW)
If the force of attraction between a 1035 kg sports car and a 10680 kg cement truck is 3.930×10-6 N, how far are they apart?
Homework Equations
F = Gm_1m_2/r^2
OK.r^2 = (6.67300 × 10^-11)(1035)(10680) / (3.930 x 10^-6)
= [(6.67300 )(1035)(10680) / (3.930)] x [10^-11/10^-6]
= [(6.67300 )(1035)(10680) / (3.930)] x 10^-5
= 18768958.6 x 10^-5
You are messing up the exponents. When you move the decimal to the left one place you must add +1 to the exponent. You subtracted instead. (Example: 456.7 = 4.567 x 10^2)= 1876895.86 x 10^-6
= 1.87689586 x 10^-12
Once you correctly find r^2, just take the square root.so how we find the distance?