Gravitational motion usingly earths radius

[AaronPrahst]

He didn't tell us that.

 

[learningphysics]

The question said it was a communication satellite. Did your instructor tell you that communication satellites typically have an orbital period of 24 hours?

Would they be allowed to use that in the problem? still a numerical value...

 

[D H]

Your instructor must have told you something. Please write the problem exactly as it was given to you.

 

[learningphysics]

Your instructor must have told you something. Please write the problem exactly as it was given to you.

The 36,000km.

 

[D H]

Learningphysics, you have a PM from me. I need to log out for now.

 

[AaronPrahst]

He stated the problem perfectly.

I just had a thought...we can't substitute 36,000km, but if he already gave it to us like that then maybe that means he just substituted it for us, so maybe we are supposed to have it already in all our equations for h.

 

[learningphysics]

If you guys are allowed to use the 36,000km...

m1g = Gm1m2/r_earth^2 (m1 = arbitrary mass. m2 = mass of earth)

so

g = Gm2/r_earth^2

where m2 is the mass of the earth...

So Gm2 = g*r_earth^2

Then plug this into the equation (as solved in the original post in this thread)

v^2 = Gm2/r

so

v^2 = g*r_earth^2/r

v^2 = g*r_earth^2/(r_earth + 36000*10^3)

plug in g=9.8m/s^2. r_earth = 6370*10^3m

at least this gives you the numerical answer you need according to the initial problem descripton... so no matter what method you use (ie a way to solve without using the 36000*10^3m), this is the numerical result you should get...

 

[AaronPrahst]

Well thanks for trying to help us but I guess our teacher is just bad and we are screwed for now.

One question though I thought Gm1=(g at Re)timesRe^2

You just have down Gm1=(g at Re)^2

 

[learningphysics]

Well thanks for trying to help us but I guess our teacher is just bad and we are screwed for now.

One question though I thought Gm1=(g at Re)timesRe^2

You just have down Gm1=(g at Re)^2

I wrote

g = Gm2/r_earth^2

Gm2 = g*r_earth^2

The "*" is multiplied... so Gm2 is g multiplied by Re^2... just as you wrote...

 

[AaronPrahst]

Oh ok I understand that now sorry I just mis-read that.

Thanks again.

 

[learningphysics]

Oh ok I understand that now sorry I just mis-read that.

Thanks again.

Did you try the formula? What number do you get for velocity?

 

[AaronPrahst]

Hmm well I plugged it in and got 1.32 m/s. Uh but I probably did something wrong...

 

[learningphysics]

Hmm well I plugged it in and got 1.32 m/s. Uh but I probably did something wrong...

v^2 = g*r_earth^2/(r_earth + 36000*10^3)

v^2 = 9.8*(6370*10^3)^2/(6370*10^3+36000*10^3)

I get v = 3063.5m/s

 

[AaronPrahst]

Ah ok yeah I got that now...I think I accidentally didn't square the Re on top.