- #1
Kitten207
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Homework Statement
Here is the problem:
http://i51.tinypic.com/6r7jts.jpg
Homework Equations
PE= mgh
KE= 1/2mv^2
I'm not sure how to go about this problem =[
Kitten207 said:Homework Statement
Here is the problem:
http://i51.tinypic.com/6r7jts.jpg
Homework Equations
PE= mgh
KE= 1/2mv^2
I'm not sure how to go about this problem =[
Kitten207 said:Ok I know that escaping means 1/2 mv2 = GMm/R.
So for the first part, I'd do Sum Ki + Sum Ui = Sum Kf + Sum Uf? From that, I'll get the velocity? Do I need to use any kinematics equations?
Kitten207 said:I am confused. To find the needed velocity:
mgh = 1/2 mv^2
v= sqrt(6gR) because height is 3R. Where do I go from there? What do I use for g?
Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. It is the energy that is stored in an object when it is raised above the ground or moved to a higher altitude.
Gravitational potential energy can be calculated using the equation GPE = mgh, where m is the object's mass, g is the acceleration due to gravity, and h is the height of the object.
The two main factors that affect an object's gravitational potential energy are its mass and its height above the ground. The higher the object is and the heavier it is, the more gravitational potential energy it will possess.
Gravitational potential energy and kinetic energy are two forms of energy that are interrelated. When an object falls from a height, its gravitational potential energy decreases while its kinetic energy increases. The total energy of the object (sum of GPE and KE) remains constant throughout the fall.
Gravitational potential energy is used in many everyday applications, such as hydroelectric power plants, where water stored at a higher altitude possesses gravitational potential energy that is converted into kinetic energy to generate electricity. It is also used in roller coasters, where the initial potential energy is converted into kinetic energy to propel the cars through the track.