Gravity and Radius of the earth problem

AI Thread Summary
The discussion revolves around measuring gravity on different floors of a building using a gravometer, with a focus on how to account for the changing mass below as one moves between floors. The initial radius of the Earth was calculated to be around 6500 km, but this value does not consider the gravitational effects of the mass beneath each floor. A key equation provided is dg/g = -2(dr/r), which relates changes in gravity to height. Participants suggest estimating the mass per floor to determine its impact on the calculated radius, emphasizing the need for a simplified approach to gauge the effect of additional mass. The conversation highlights the importance of accurately incorporating gravitational variations into the radius calculation.
J.Sterling47
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Homework Statement


Hey guys, I have a problem where we measured the gravity on separate floors of a building using a gravometer. It gave us values in mgals. So each floor has a distance of 0.5m. How do we take this into account as we move up and down the floors? As we move up, there's and increase of mass below us and vice versa as we go down. The goal is to calculate the radius of the Earth using this method.

Homework Equations


dg/g = -2(dr/r) where dg is the change in gravity per floor and dr is the height of each floor. We got the radius to be close at about 6500km, but without taking into account the changing of the mass below.

The Attempt at a Solution


Don't really know where to start
 
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J.Sterling47 said:
So each floor has a distance of 0.5m.
You sure about that?
 
DaveC426913 said:
You sure about that?
Yeah sorry it was supposed to be 5m. I converted it wrong but yea
 
J.Sterling47 said:
We got the radius to be close at about 6500km, but without taking into account the changing of the mass below.
If you are concerned about that, the first thing is to get an upper bound on how much difference that will make. Estimate the mass per floor of the building. Be generous. Likewise, maximise the effect by assuming all that extra mass is only one floor below (for simplicity). How much difference will that make to your answer?
 
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