Greatest RMS voltage generated in a circuluar loop antenna

AI Thread Summary
The discussion centers on calculating the greatest RMS voltage generated by a circular loop antenna with a radius of 30.0 cm and located 14.0 km away, using a frequency of 170 MHz. The key equation mentioned is V = wA, where A represents the area of the loop. There is confusion regarding whether to use V = wA/√2 for RMS voltage or to integrate for a continuous distribution. Participants are seeking clarification on the appropriate method to calculate the RMS voltage in this scenario. The thread highlights the need for a clear approach to integrating or applying the RMS formula correctly.
Winzer
Messages
597
Reaction score
0
1. Homework Statement [/
What is the greatest RMS voltage generated in a circuluar loop antenna which is 30.0 cm in radius (also located 14.0 km away)

Homework Equations


V=wA


The Attempt at a Solution


So the frequency is 170MHz.
My question is how to deal with the root mean squared.
is it:
V=\frac{wA}{\sqrt 2}? A is area by the way
 
Physics news on Phys.org
do i perform V=\frac{wA}{\sqrt 2}
or do i need to intergrate since this is a continious distribution?
V_rms= \sqrt ( \frac{1}{r} \int_0^r (wA)^2 dr)
 
anyone?
 
:cry:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top