MHB Grothendieck Problem: Solving $(*)$ Algebraically

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The discussion centers on the Grothendieck problem related to differential equations, specifically the conjecture that if a certain differential equation has n linearly independent solutions modulo almost all primes, then it also has n linearly independent algebraic solutions in the complex power series field. The user seeks resources to better understand this conjecture and asks for clarification using the example of the differential equation xy' - ky = 0. They aim to determine a prime such that for all larger primes, the equation has a solution in the field of formal power series. The conclusion drawn is that if the conditions are met, the differential equation will indeed have an algebraic solution in the complex power series field.
mathmari
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Hey! :o

Could you suggest me a book or a link where I can find some information about the Grothendieck problem about differential equations?

The Grothendieck problem that I am reffering to is the following:

$$\alpha_n(x)y^{(n)}(x)+\dots +a_1 (x)y'(x)+a_0(x)y(x)=0, a_i \in \mathbb{Z}[x]\ \ \ \ (*)$$

We suppose that for almost each prime $p$, $(*)$, modulo $p$, has $n$ linearly independent solutions (powerseries in $\mathbb{F}_p((x))$, with field of constants $\mathbb{F}_p((x^p))$). Then $(*)$ has $n$ linearly independent solutions (powerseries in $\mathbb{C}((x))$ with field of constants $\mathbb{C}((x))$) and all are algebraic.
 
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(I think that this problem is called Grothendieck-Katz conjecture.)Could you explain to me the above problem when we have for example the differential equation $xy'-ky=0, k\in \mathbb{Z}$ ?

We have to find a prime such that for all primes $p$ greater or equal than that one, it stands that modulo $p$ the differential equation has in this case one solution in $\mathbb{F}_p((x))$.

Then the differential equation has one algebraic solution in $\mathbb{C}((x))$.

Is this correct?
 

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