Group theory and Spacetime symmetries

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SUMMARY

A manifold with a metric tensor is spherically symmetric if the Lie algebra of its Killing vector fields contains a sub-algebra isomorphic to SO(3). This relationship is crucial for deriving the general form of a spherically symmetric metric, which is essential for obtaining Schwarzschild's solution through the vacuum Einstein Field Equations (EFE). The connection between space-time symmetries and the rotation group is established through the isometry group of the manifold, which includes a subgroup isomorphic to SO(3), indicating that the orbits are 2-spheres. Understanding this relationship is fundamental for grasping the symmetries encoded in the Killing vectors of a (pseudo-)Riemannian manifold.

PREREQUISITES
  • Understanding of manifold theory and metric tensors
  • Familiarity with Lie algebras and Killing vector fields
  • Knowledge of general relativity and the vacuum Einstein Field Equations (EFE)
  • Basic concepts of group theory, specifically SO(3)
NEXT STEPS
  • Study the derivation of Schwarzschild's solution using vacuum Einstein Field Equations
  • Explore the properties and applications of Killing vectors in (pseudo-)Riemannian manifolds
  • Investigate the relationship between isometry groups and symmetry in differential geometry
  • Learn about the Lie bracket operation and its implications for vector fields
USEFUL FOR

The discussion is beneficial for theoretical physicists, mathematicians specializing in differential geometry, and students of general relativity seeking to deepen their understanding of spacetime symmetries and their mathematical foundations.

cesiumfrog
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"A manifold (with a metric tensor) is said to be spherically symmetric iff the Lie algebra of its Killing vector fields has a sub-algebra that is the Lie algebra of SO(3)." Why?

The statement is paraphrased from texts such as Schutz or D'Inverno, where it is always expressed like a definition with no explanation.. except to note that this definition is sufficient to calculate the general form of a spherically symmetric metric/line-element (rather than just writing one down intuitively), which then might be used (in combined with the vacuum-EFE) to obtain Schwarzschild's solution. Could anyone point me to an explanation or proof for the statement?

It does make sense that there should be some relationship between the space-time symmetries and the familiar rotation group, but why do we know the relationship to have this specific form?
 
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cesiumfrog said:
"A manifold (with a metric tensor) is said to be spherically symmetric iff the Lie algebra of its Killing vector fields has a sub-algebra that is the Lie algebra of SO(3)." Why?

Think about the more familiar definition of spherical symmetry that one finds in, say, Wald:

A spacetime is spherically symmetric if its isometry group contains a subgroup isomorphic to SO(3) and whose orbits are 2-spheres.

(At least I think that's how Wald defines it; it's certainly the first definition that trips off my tongue, and I know that I learned this kind of thing from Wald.) Can you see how to relate the statement you qouted to the one I've given here?

Presumably, for example, you're aware that the symmetries of a (pseudo-)Riemannian manifold are encoded in the set of Killing vectors (if it exists) of that manifold. And presumably you know that if a complete set of Killing vectors encodes all the information about the symmetries of the manifold, then a subset of the set of Killing vectors could encode information about a smaller symmetry such as the rotational invariance of the manifold?

Can you see a way to combine this fact with the fact that a natural operation on pairs of vector field is the Lie bracket? And can you see how this will lead you to -- at the very least -- an intuitive acceptance of the statement?
 

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