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beethoven'smahomeboy
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In the context of Newtonian mechanics, why are gyroscopes good navigational instruments? What is the best shape for a gyroscope?
Gyroscopes as navigational devices
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Gyroscopes are effective navigational instruments due to their ability to maintain a constant rotational axis, allowing for tracking of relative movement without external references like GPS. Their design, particularly when counterweighted, enables them to align with the Earth's axis, enhancing navigation accuracy. This principle is utilized in various applications, including ICBMs and tanks, where precise orientation is crucial. Bicycle wheels also function as gyroscopes, providing stability while riding. Overall, gyroscopes play a vital role in inertial navigation systems by leveraging their inherent properties.
Hello,
I'm joining this forum to ask two questions which have nagged me for some time. I am in no way trolling. They both are presumed obvious, yet don't make sense to me. Nobody will explain their positions, which is...uh...aka science. I also have a thread for the other question.
Yes, I'm questioning the most elementary physics question we're given in this world.
The classic elevator in motion question: A person is standing on a scale in an elevator that is in constant motion...
This is (ostensibly) not a trick shot or video*.
The scale was balanced before any blue water was added.
550mL of blue water was added to the left side.
only 60mL of water needed to be added to the right side to re-balance the scale.
Apparently, the scale will balance when the height of the two columns is equal.
The left side of the scale only feels the weight of the column above the lower "tail" of the funnel (i.e. 60mL).
So where does the weight of the remaining (550-60=) 490mL go...
Let us take the Ampere-Maxwell law
$$\nabla \times \mathbf{B} = \mu_0\,\mathbf{J}+\frac{1}{c^2}\frac{\partial \mathbf{E}}{\partial t}.\tag{1}$$
Assume we produce a spark that is so fast that the ##\partial \mathbf{E}/\partial t## term in eqn.##(1)## has not yet been produced by Faraday’s law of induction
$$\nabla \times \mathbf{E}=-\frac{\partial \mathbf{B}}{\partial t}\tag{2}$$
since the current density ##\mathbf{J}## has not yet had time to generate the magnetic field ##\mathbf{B}##.
By...