- #1
Bassalisk
- 947
- 2
Hello,
I want to come clean with rectifiers. Mainly half wave rectifiers with filter.
[PLAIN]http://www.sciencelobby.com/diodes/images/reservoir-capacitor.gif
Assume these conditions. Diode CVD is 1 V. At t=0 s, or initially, capacitor does not have starting charge. So everywhere else potentials are 0.
When we turn on the circuit, at first, diode won't conduct until 1 V is reached. That is small compared to those 12 volts. Diode will conduct until capacitor is fully charged, or until sinusoid reaches its peak(maximum).
After that, sinusoid starts to drop, but we have that voltage on the capacitor which is now higher than the voltage of the source. So diode doesn't let the current run in other direction and it is in reverse bias. Diode won't let any current until voltage of the source becomes higher than that on the capacitor right? And then capacitor recharges etc.
My question here is:
Did I got this right? How do we calculate output voltage? Its not steady because of that ripple.
If you calculate Vdc=Vmax-Vdiode, Why? Why would you subtract the diode voltage of the Max value because, sinusoid still reaches it maximum.
Does diode gets voltage drop like resistors? Or it just behaves like an element that needs certain voltage to let current through?
(and thanks PF and EE fellows I just passed all my exams with decent marks.)
I want to come clean with rectifiers. Mainly half wave rectifiers with filter.
[PLAIN]http://www.sciencelobby.com/diodes/images/reservoir-capacitor.gif
Assume these conditions. Diode CVD is 1 V. At t=0 s, or initially, capacitor does not have starting charge. So everywhere else potentials are 0.
When we turn on the circuit, at first, diode won't conduct until 1 V is reached. That is small compared to those 12 volts. Diode will conduct until capacitor is fully charged, or until sinusoid reaches its peak(maximum).
After that, sinusoid starts to drop, but we have that voltage on the capacitor which is now higher than the voltage of the source. So diode doesn't let the current run in other direction and it is in reverse bias. Diode won't let any current until voltage of the source becomes higher than that on the capacitor right? And then capacitor recharges etc.
My question here is:
Did I got this right? How do we calculate output voltage? Its not steady because of that ripple.
If you calculate Vdc=Vmax-Vdiode, Why? Why would you subtract the diode voltage of the Max value because, sinusoid still reaches it maximum.
Does diode gets voltage drop like resistors? Or it just behaves like an element that needs certain voltage to let current through?
(and thanks PF and EE fellows I just passed all my exams with decent marks.)
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