Hard Physics Problem - Centripetal Force

AI Thread Summary
To determine the maximum period of rotation for riders on a cylindrical amusement ride, it is essential to analyze the forces acting on the riders when the floor is lowered. The centripetal force, which keeps the riders against the wall, is influenced by the speed of rotation and the radius of the cylinder. A free-body diagram can help visualize the forces, excluding centripetal force itself. The coefficient of friction between the riders and the wall is also a critical factor in preventing them from sliding down. Understanding these dynamics is crucial for solving the problem effectively.
Rbethell16
Messages
10
Reaction score
0

Homework Statement


A popular amusement ride operates as follows: Riders enter the cylindrical structure when its stationary with the floor. They then stand against the wall as the cylinder then begins to rotate. When it is up to speed, the floor is lowered, leaving the riders suspended against the wall high above the floor. What is the maximum period of rotation necessary to keep the riders from sliding down the wall when the floor is lowered.

Homework Equations


Fc = Vr^2/m

The Attempt at a Solution


I truly do not know where to begin
 
Physics news on Phys.org
Rbethell16 said:

The Attempt at a Solution


I truly do not know where to begin

Start by drawing a free-body diagram, remember that centripetal force should not be on your diagram.
 
Rbethell16 said:
I truly do not know where to begin

Perhaps with the specification of the coefficient of friction for the wall?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top