Have I just invented a new axiom?

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I doubt it but I was doing some work on trying to remove time from Classical Physics (just for the hell of it) and I came across a formula that made me go "huh, not seen that before, but it's kind of neat."

Just out of curiosity has anyone seen this formula before?

X = √ ((X/2Π) * (X*2Π))
 
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If you mean ##x = \sqrt{\frac{x}{2\pi}x2\pi}##, where's the point?
 
No more than it's an interesting pattern and I thought I'd post out of curiosity as to whether seen it before.
 
Doesn't work if ##x=-1##.
 
Whatever this formula is or where it comes from, it's not an axiom. You should consult a dictionary for a proper definition of that term.
 
Ah a classic example of a tongue-in-cheek post title being met with derision and scorn (it was a play on the classic "HAVE I JUST INVENTED A NEW FORMULA?!" posts you get on things like this.

I am genuinely interested if anyone has seen this pattern before because this is the first time I came across it, and it just seemed kind of neat.
 
CasualCalculus said:
Ah a classic example of a tongue-in-cheek post title being met with derision and scorn (it was a play on the classic "HAVE I JUST INVENTED A NEW FORMULA?!" posts you get on things like this.

I am genuinely interested if anyone has seen this pattern before because this is the first time I came across it, and it just seemed kind of neat.

Yes, it's a neat pattern and formula. But it's wrong. Try ##x=-1##.
 
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Yeah, hubris took hold before I checked it with x = -1
 
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  • #10
CasualCalculus said:
Just out of curiosity has anyone seen this formula before?

X = √ ((X/2Π) * (X*2Π))
Or in an easier-to-read form:
fresh_42 said:
If you mean ##x = \sqrt{\frac{x}{2\pi}x2\pi}##, where's the point?

CasualCalculus said:
No more than it's an interesting pattern and I thought I'd post out of curiosity as to whether seen it before.
The right side simplifies to ##\sqrt{x^2}##, which is NOT equal to x. It is true, however, that ##\sqrt{x^2}## = |x|.
 
  • #11
It is true that ##|x|=\sqrt{(x/2π)2πx}##, but it is also true that ##|x|=\sqrt{(x/79)79x}## and ##|x|=\sqrt{(x/y)xy}##. This axiom already exists:
##|x|=\sqrt{x^2}##.
 
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