Having a hard time with visual of FBD

Click For Summary

Homework Help Overview

The discussion revolves around the construction of position vectors in a three-dimensional space, specifically focusing on point D in relation to other points A, B, and C. Participants are grappling with the correct representation of these vectors and the implications of the geometry involved, particularly concerning the sagging of a rope.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to derive the position vector for point D, questioning their initial assumptions about the z-component. Some suggest redrawing the diagram from different perspectives to clarify the relationships between the points. Others express frustration over repeated calculations leading to incorrect results and seek validation of their approaches.

Discussion Status

There is an ongoing exploration of the position vectors and their components, with some participants providing specific values for x, y, and z. Guidance has been offered regarding the need to consider the geometry of the problem more carefully, and there is acknowledgment of differing setups in solutions. However, no consensus has been reached on the correct approach or values.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There is also a mention of the complexity involved in visualizing the three-dimensional aspects of the problem.

Saladsamurai
Messages
3,009
Reaction score
7
I am trying to write a position vector for point D

Picture3.png


I originally thought that the z component was 0...but now common sense is telling me that it can't be...the rope must be sagging.

Are my first to components correct or am I visualizing this incorrectly? :
8i+7j-(something)k <---or are my x and y's wrong too?
 
Physics news on Phys.org
look more carefully at the diagram... (for D) x and y are both smaller than you have stated, and z is not zero.
It may help to try to redraw the diagram looking from other perspectives, starting with looking downwards.
Here's a clue... x=3 for point D.
 
Last edited:
mda said:
look more carefully at the diagram... (for D) x and y are both smaller than you have stated, and z is not zero.
It may help to try to redraw the diagram looking from other perspectives, starting with looking downwards.
Here's a clue... x=3 for point D.
And it is y=2 correct And z=-2?

I need to look at the fact that the ropes AD and DC are not parellel to the x and y axes so I can't use the 7 and 8 foot measurements that correspond.

Maybe I should redraw the 3-D case in two 2-D cases instead?
 
Last edited:
I am so goddamn sick of doing all of these calculations just to get the wrong answer! WTF WTF WTF WTF!
 
Here is my work. This is my third attempt in 3 hours. Am I F'ing stupid? It's okay to tell me. Disregard the attempt to solve the equations. It is a retarded substitution. I am not even sure it would work. But, I now see the easy elimination. But the equations themselves are somehow incorrect.

When I enter them into an online solver, only T_A comes out correct. I don't know if that helps me figure out where my error is...but this is killing me.

The equations are the ones marked (1) (2) and (3)

Picture4.png
 
Assume the position vector of B as (0,0,0). Wright down the position vectors of A, D, C. and then find vector DA, DB and DC. Find the unit vectors of them. Let p, q and r be the magnitudes of the tensions along DA, DB and DC. consider the points A', B' and C' are the points on the plane containing D which is parallel to the plane ABC. Now take the projection of the three tensions on this plane. For equilibrium two conditions should be satisfied. i) Z- components of the tensions should be equal to 20lb, and projections of the tensions should satisfy the Lami's theorem. You can find out the required angles by noting down the proper distances.
 
0 5546 Tc is wrong. It should be 0.3244Tc. Try this value.
 
rl.bhat said:
0 5546 Tc is wrong. It should be 0.3244Tc. Try this value.

Why? 2/3.606=.5546
 
I have been vindicated! My instructor posted an old solution to the problem in which it was set up differently. My position vectors should be correct.
 
Last edited:
  • #10
rc should be 0i + 7j + 0k and rdc should be -3i + 5j + 2k
 
  • #11
rl.bhat said:
rc should be 0i + 7j + 0k and rdc should be -3i + 5j + 2k

Thank you sir!

Casey
 
  • #12
Say, Saladsamurai, what are you using to post your attachments? I'm just getting "red x's" at your illustrations...
 
  • #13
Saladsamurai said:
I am so goddamn sick of doing all of these calculations just to get the wrong answer! WTF WTF WTF WTF!

heh yes I also hate position vectors but there are much worse problems for that then the type you posted. Mid term exam had a equivalent systems question and there were dimensions everywhere, at least 20 dimensions markings - in millimeters as well of course. :cry:
 
  • #14
dynamicsolo said:
Say, Saladsamurai, what are you using to post your attachments? I'm just getting "red x's" at your illustrations...

Photobucket...is anyone else seeing red x's??

Casey
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
8
Views
1K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
24
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
5K
Replies
13
Views
2K