Engineering Having trouble calculating the air supply necessary for combustion

AI Thread Summary
The calculation of air supply for combustion is incorrect due to a misunderstanding of moles. The correct interpretation shows that 1 mole of air consists of 0.2 moles of O2 and 0.8 moles of N2. In this case, there are actually 13.5 moles of O2 present, not air. The stoichiometric amount of N2 must also be considered in the calculation. Accurate understanding of these ratios is essential for correct combustion calculations.
Remusco
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Homework Statement
Fuel is burned in a furnace with 12% excess air to minimize the formation of partially oxidized product. The average molecular weight of the fuel is 126. The overall complete stoichiometric combustion reaction is:
Relevant Equations
C_9H_18 + 13.5 O_2 +50.8 N_2 ---> 9CO_2 +9H_2O + 50.8N_2
I'm surprised that I'm getting this wrong. Seems like everything checks out in my calculation. Correct answer is supposedly C.

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Your mistake is in saying you have 13.5 moles of air. 1 mole of air is 0.2 mol O2 + 0.8 mol N2. Actually you have 13.5 moles O2 and the stoichiometric amount of N2.
 
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mjc123 said:
Your mistake is in saying you have 13.5 moles of air. 1 mole of air is 0.2 mol O2 + 0.8 mol N2. Actually you have 13.5 moles O2 and the stoichiometric amount of N2.
Makes sense. Thanks.
 
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