Having trouble understanding the relationship between these expressions

AI Thread Summary
The discussion centers on understanding the relationship between the expressions √(MgL/m) and L/t in the context of measuring free-fall acceleration on a small planet. The key point is that wave speed (v) is equal to both √(T/u) and L/t, where T is tension and u is mass per unit length. Participants clarify that the last equality is not derived from the first expression but rather from the definition of speed as distance over time. There is some confusion regarding the algebraic rearrangement of the equations, particularly since it isn't found in the referenced textbook. Overall, the focus is on clarifying the derivation and application of these equations in the problem context.
coldjeanz
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I understand everything up until:

√MgL/m = L/t

Why is that equal to L/t?

I also don't understand this either:

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This is the problem itself however I don't feel it's that important since I am trying to figure out how they are arriving at their conclusions.

An astronaut on a small planet wishes to measure the local value of the free-fall acceleration by timing pulses traveling down a wire that has an object of large mass suspended from it. Assume a wire has a mass of 4.10 g and a length of 1.60 m and that a 3.00 kg object is suspended from it. A pulse requires 43.6 ms to traverse the length of the wire. Calculate g of planet from these data. (You may ignore the mass of the wire when calculating the tension in it.)
 
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They are not saying that the last equality follows from something about \sqrt{MgL/m}, but rather that the wave speed v is equal to both \sqrt{T/u} AND L / t (since speed is just distance divided by time).

The second section is just an algebraic rearrangement of the second equation in the first section.
 
Yeah okay that went through my head for a split second but I couldn't find that in my book so I didn't know where they pulled it from. Thank you!
 
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