Heat Transfer Question Interpretion

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SUMMARY

The discussion centers on calculating the average convection heat transfer coefficient and the rate of heat transfer for a 4x4m flat plate at 80°C subjected to air at 20°C and 10 m/s. The total drag force on the upper surface is given as 2.4N. A key point of confusion arises regarding the use of total surface area in calculations; while the question specifies the upper surface, the solution incorrectly considers both sides, leading to discrepancies in results. The correct approach is to utilize only the upper surface area of 16m² for accurate calculations.

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  • Understanding of heat transfer principles, specifically convection.
  • Familiarity with drag force calculations in fluid dynamics.
  • Knowledge of the heat momentum transfer analogy.
  • Basic proficiency in thermal analysis of flat plates.
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  • Investigate the effects of surface area on heat transfer calculations.
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Hello, i have a simple question regarding a problem I am solving. Here it is:

A 4x4m flat plate maintained at a constant temperature of 80 degree Celsius subjected to parallel flow of air at 1 atm,20 degree celsius and 10m/s.The total drag force acting on the UPPER surface of plate is measured to be 2.4N.Using heat momentum transfer analogy,determine the average convection heat transfer coefficient and the rate of heat transfer between the UPPER surface of the plate and air.

I had the solution for this problem , however what i don't understand is that why is the total surface area used in the calculations 32(Which means both sides of the plate) WHEN it is clearly stated in the question that only the UPPER surface is involved. Can anyone enlighten me why is both sides of the plate used even though they said total drag force on the UPPER surface of plate is 2.4N and want us to determine the rate of heat transfer between the UPPER surface of plate and air. In my case i used 16 for surface area and subsequently got the wrong answers.
 
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This looks like a homework question to me.

Based on what you've written for the problem statement, only the upper surface's surface area should be taken into account, so it could be the "solution" you have is wrong.
 

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