Height Ratio of A Coin below the Water

willydavidjr
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A coin is at the bottom of a pool with a depth of h^l[m]. The diagram I provided below shows the coin can appear to be in a place shallower than its actual depth.

Looking perpendicularly onto the water surface ( i\cong 0, r\cong 0 ), the coin looked as if it were in a place with depth h[m]. FInd the ratio of h^l/h of the two heights.

This is the site of the diagram: www.geocities.com/willydavidjr/coin ...
 

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Well, where's your solution? Apply Snell's law of refraction--and a bit of trig--and you can solve it. Hint: Consider small angles of incidence and refraction (close to the normal).
 

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