Help and explain to me how to solve it ?(new question )

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The discussion revolves around several mathematical problems related to savings, loans, and series expansions. A student needs to calculate how many months it will take to save enough for an encyclopedia set while earning interest on his savings. Additionally, a house buyer must determine the monthly repayment amount for a loan over 15 years with a fixed interest rate. The thread also includes tasks involving polynomial expansions and geometric series, emphasizing the importance of showing effort in problem-solving for better assistance. Participants are encouraged to focus on one or two problems at a time for clarity.
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Homework Statement


1)a student saves his pocket money with the intention to buy an encyclopedia set costing RM1200.If he saves RM50 in the bank each month and the bank pays him an interest of ½ % per month , how many months has he got to saves before he can afford to buy the encyclopedia?

2)a house buyer borrow RM50000 from a bank to buy a house which costs RM70000. The rate of interest charged by the bank is 9% per annum ,and is calculated based on the amount outstanding at the beginning of each year. The house buyer is required to repay his loan in monthly installments for a period of 15 years. Assuming that the rate of interest is fixed for the entire duration of the loan ,find the amount per month he has to repay the bank .

3)find the coefficient of terms in as indicated in the following expansions.
(1+x^2)(2-3x)^7, term in x^3

4)expand the following function as a series in ascending powers of x up to and including the term in x^3. State the range of value of x for the expansion is valid
a)(1+x+x^2)^-1
b)(1-x-2X^2)^5

5)find the sum to the nth term of geometric series 108+60+33/ 1/3+…….if s is the smallest number which exceeds this for all values of n ,find the value of s .find also the smallest value of n such that the sum of the series exceeds 99% of the values of s.


{b]2. Homework Equations [/b]
s=a/(r-1) or...


The Attempt at a Solution


out of ideal
 
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According to the rules of this forum, you have to make an effort at solving the problems you post before we can give you any help.

Also, you will probably get more help (assuming you show an effort) if you put only one or two problems in a thread.
 
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