1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

HELP [Confused] Case: Fuji Film Introduces Aps

  1. Mar 23, 2007 #1
    HELP!!! [Confused] Case: Fuji Film Introduces Aps

    In the early 1990s, Fuji Photo Film, USA, joined forces with four of its rivals to create the Advanced Photo System (APS), which is hailed as the first major development in the film industry since 35 - millimeter technology was introduced. In February 1996, the new 24 millimeter system, promising clearer and sharper pictures, was launched. By the end of the year, the lack of communications and a limited supply of products made retailers angry and consumers baffled. Advertising was almost nonexistent. Because the product was developed by five industry rivals, the companies had enacted a secrecy agreement in which no one outside of company management, including the company's sales force, would know details about the product until each company introduced its APS products on the same day. When the product was actually introduced, it came with little communication to retailers about the product, virtually no training of sales representatives on the product ( so that they could demonstrate and explain the features ), and a great underestimation of demand for the product. Fortunately, Fuji pressed on by taking an "honesty is the best policy" stance and explaining to retailers and other costumers what had happened and asking for patience. In addition, Fuji increased its research to better ascertain market positioning and size. By 1997, Fuji had geared up production to meet the demand and was increasing customer promotion. APS products were on the road for success. By 1998, APS cameras owned 20% of the point and shoot camera market.

    1. As stated, by 1998 APS cameras owned 20% of the point and shoot camera market. Now it is the year 2003 and the market share might be nearer to 40%. Suppose 30 cusomers from the point and shoot camera market are randomly selected. If the market share is really .40 , what is the expected number of point and shoot camera customers who purchase an APS camera? What is the probability that six or fewer purchases and APS camera? Suppose you actually got six or fewer APS customers in the sample of 30. Based on the probability just calculated, is this enogh evidence to convince you that the market share is 40% Why or why not?

    2. Suppose customer complaints on the 24 millimeter film are poison distributed at an avegare rate of 2.4 complaints/100,000 rols sold. Suppose further that Fuji is having trouble with shipments being late and one batch of 100,000 rolls yields seven complaints from customers. Assuming that it is unacceptable to management for the average rate of complaints to increase, is this enough evidence to convince management that the average rate of complaints has increased, or can it be written off as a random occurence that happens quite frequently? Produce the Poisson distribution for this question and discuss its inplication for this problem.

    3. One study of 52 product launches found that those undertaken with revenue growth as tha main objective are more likely to fail than those undertaken to increase customer satisfaction or to create a new market such as the APS system. Suppose of the 52 products launched, 34 were launched with revenue growth as the main objective and the rest were launched to increase cusotmer satisfaction or to create a new market. Now suppose only 10 of these products were successful ( the rest failed) and seven were products that were launched to increase customer satisfaction or to create a new market. What is the probability of this result occuring by chance? What does this probability tell you about the basic premise regarding the importance of the main objective?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Mar 26, 2007 #2

    berkeman

    User Avatar

    Staff: Mentor

    Welcome to the PF, yanip. You are required to show your own work on homework problems before we can help you. What are the relevant equations and concepts involved in calculating these probabilities? How would you go about applying them?
     
  4. Mar 26, 2007 #3
    I use minitab but tried to solve using the formula.
    For Q1:
    I got these answers because P(x)= nCx * p^x * q^ n-x
    n=30, x<=6, p=.4
    Meaning
    30 nCr 6 *(.40)^6 * (.60)^24= .0116
    30 nCr 5 *(.40)^5 * (.60)^25= .0041
    30 nCr 4 *(.40)^4 * (.60)^26= .0012
    30 nCr 3 *(.40)^3 * (.60)^27= .0000
    30 nCr 2 *(.40)^2 * (.60)^28= .0000
    30 nCr 1 *(.40)^1 * (.60)^29= .0000
    30 nCr 0 *(.40)^0 * (.60)^30= .0000

    I don't know how to figure out the graph through mini tab and to solve Q3

    Thank you.
     
  5. Aug 10, 2007 #4
    solution of 1st que

    n=30
    p=.4
    1-p=.6
    expected=12
    p(atleast six)=p(<=6)=.0172
     
  6. Aug 10, 2007 #5
    plz send a reply
     
  7. Aug 10, 2007 #6
    I use minitab but tried to solve using the formula.

    For Q1:
    I got these answers because P(x)= nCx * p^x * q^ n-x
    n=30, x<=6, p=.4
    Meaning
    30 nCr 6 *(.40)^6 * (.60)^24= .0116
    30 nCr 5 *(.40)^5 * (.60)^25= .0041
    30 nCr 4 *(.40)^4 * (.60)^26= .0012
    30 nCr 3 *(.40)^3 * (.60)^27= .0000
    30 nCr 2 *(.40)^2 * (.60)^28= .0000
    30 nCr 1 *(.40)^1 * (.60)^29= .0000
    30 nCr 0 *(.40)^0 * (.60)^30= .0000
     
    Last edited: Aug 10, 2007
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: HELP [Confused] Case: Fuji Film Introduces Aps
Loading...