Help finding multiplicity and zeros?

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pita0001

(x+4) (x-2)^3 (x^2+2x-8)

would it be -4 multiplicity of 2
and 2 multiplicity of 4?

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MarkFL

Gold Member

MHB

Yes, that's correct since the quadratic factor is the product of the other two linear factors.

HallsofIvy

in other words,
[tex](x+ 4)(x- 2)^3(x^2- 2x- 8)= (x+ 4)(x- 2)^3(x- 2)(x+ 4)= (x+ 4)^2(x- 2)^4[/tex]
as I am sure you realized.

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