Help finding the derivative for Faraday's equation?

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To find the derivative of the magnetic flux (dΦB/dt) with respect to time, use the formula dΦB/dt = ΔΦB/Δt. Given a time interval of 0.0085 seconds and a magnetic flux change of 0.0008 Wb, the calculation yields a derivative of approximately 94.12 Wb/s. The user expresses uncertainty in their calculus skills, indicating a need for clarification on the process. The provided link may offer additional insights into related equations. Understanding these calculations is essential for applying Faraday's law of electromagnetic induction effectively.
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I need to find the derivative with respect to time of the magnetic flux (dΦB/dt). I have a time of .0085 seconds, and a magnetic flux of .0008 Wb. I am a little hazy on my calc skills.
 
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It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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