Help Freefalling object problem

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To solve the problem of a freely falling object that takes 1.60 seconds to travel the last 23.5 meters before hitting the ground, two equations of motion must be applied. The initial velocity for the last segment is zero, and the final velocity at the end of this segment can be calculated using the equation v = u + gt. The distance covered in the last 23.5 meters can be found using s = ut + 1/2 gt^2. Once the final velocity for the last segment is determined, it can be used as the initial velocity for the height from which the object fell. This approach will yield the total height from which the object was dropped.
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Homework Statement


A certain freely falling object requires 1.60 s to travel the last 23.5 m before it hits the ground. From what height above the ground did it fall?

Homework Equations


This is my last question on my online homework. Help! I have gotten answers, but the computer says they wrong.

The Attempt at a Solution


I know I have to set up two different equations, one for the last 23.5 m and one from the point that it fell at to the last 23.5m. I know the initial Velocity of the object is 0, and the final velocity of the initial drop is the initial velocity of the last 23.5m. Please help! I have tried it numerous times. My homework is due in 4 hours... Thanks :)
 
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You know the equations for a faling object.
v = u + gt
s = ut + 1/2 gt^2
v^2 = u^2 + 2gs

(s=distance, u=initial velocity, v=final velocity)
So you can work out the initial velocity ofthe last stage, and then use that as the final velocity of the first stage.
 

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