Help I need to find out whether activation energy can be calculated this way ?

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    Activation Energy
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SUMMARY

The discussion centers on calculating the activation energy (Ea) for the reaction S2O82- + 2 I- → SO42- + I2 using the Arrhenius equation. Two experiments yielded rate constants K1 = 0.0594 at 21°C and K2 = 0.06 at 22°C. The calculated activation energy was determined to be 7.207 kJ/mol using the formula Ea = -R * ln(K1/K2) / (1/T1 - 1/T2). The user expresses uncertainty about the frequency factor A, which is necessary for further calculations.

PREREQUISITES
  • Understanding of the Arrhenius equation and its components
  • Basic knowledge of thermodynamics, specifically activation energy
  • Familiarity with rate constants and their significance in chemical kinetics
  • Ability to perform logarithmic calculations and unit conversions
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  • Research the concept of the frequency factor A in the Arrhenius equation
  • Learn how to experimentally determine activation energy using different methods
  • Explore the impact of temperature on reaction rates and activation energy
  • Investigate the significance of the Arrhenius equation in chemical kinetics
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Chemistry students, researchers in chemical kinetics, and anyone involved in experimental thermodynamics will benefit from this discussion.

himynameis
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i did an experiment, i noted the tempreture and found rate constant.
My friend did the same experiment and she found rate constant and noted the tempreture.. The tempreture differs by one degree. Can i calculate tempreture like this...?

S2O82-(aq) + 2 I-(aq)  SO42-(aq) + I2(aq)

Friend: K1: 0.0594 at t1: 21oC = 294 K
Ours = K2: 0.06 and t2: 22oC. 295 K


In (0.0594 /0.06) = Ea / 8.314 x ( 1/ 294- 1/295 )
-0.01 = Ea / 8.31 x (1.153x10-5)
Ea= 0.01x 8.31 / 1.153x10-5)
Ea = 7207.28 J/mol

= 7.207 KJ mol

Is this possible?

please help me! :( So for this reaction is the Ea 7.207

I would have done Just used my rate constant and tempreture to wwork out Ea but I don't know the Frequency factor A! I can't find this anywhere...
 
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can anyone help me is this possible?
 

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