Help I need to find out whether activation energy can be calculated this way ?

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    Activation Energy
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The discussion centers on calculating activation energy (Ea) for a chemical reaction using rate constants and temperatures from two experiments. The user and their friend obtained slightly different rate constants at temperatures differing by one degree Celsius. They used the Arrhenius equation to derive an Ea of approximately 7.207 kJ/mol based on their data. However, the user expresses uncertainty about the accuracy of this calculation and the need for the frequency factor (A) to confirm their results. The query seeks validation of the Ea calculation and assistance in finding the frequency factor.
himynameis
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i did an experiment, i noted the tempreture and found rate constant.
My friend did the same experiment and she found rate constant and noted the tempreture.. The tempreture differs by one degree. Can i calculate tempreture like this...?

S2O82-(aq) + 2 I-(aq)  SO42-(aq) + I2(aq)

Friend: K1: 0.0594 at t1: 21oC = 294 K
Ours = K2: 0.06 and t2: 22oC. 295 K


In (0.0594 /0.06) = Ea / 8.314 x ( 1/ 294- 1/295 )
-0.01 = Ea / 8.31 x (1.153x10-5)
Ea= 0.01x 8.31 / 1.153x10-5)
Ea = 7207.28 J/mol

= 7.207 KJ mol

Is this possible?

please help me! :( So for this reaction is the Ea 7.207

I would have done Just used my rate constant and tempreture to wwork out Ea but I don't know the Frequency factor A! I can't find this anywhere...
 
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can anyone help me is this possible?
 

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