Help Kinematics in 2d Question

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The discussion revolves around a kinematics problem involving the water at Niagara Falls, specifically calculating the vertical distance at which the water's velocity vector points downward at a 49.4-degree angle. The horizontal speed of the water is given as 1.23 m/s, leading to the use of the tangent function to find the vertical component of velocity (Vy). The equation tan(49.4) = Vy/1.23 is established to solve for Vy, followed by applying the kinematic equation (Vy)^2 = u^2 + 2gy to determine the vertical displacement. Despite following the outlined steps, the user ultimately reported an incorrect solution and expressed frustration over failing the problem. The discussion highlights the challenges of applying kinematic equations in two-dimensional motion scenarios.
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Help! Kinematics in 2d Question!

Suppose the water at the top of Niagara Falls has a horizontal speed of 1.23 m/s just before it cascades over the edge of the falls. At what vertical distance below the edge does the velocity vector of the water point downward at a 49.4 degrees angle below the horizontal?
 
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The angle is given as 49.4degrees...
And you know that tan of an angle will be y/x, and you're given the x velocity component, 1.23m/s...
Now, you can form an equation...
tan 49.4 = Vy/1.23
Solve it for Vy... (Vy is that final vertical velocity)
Then, to find the vertical displacement, use the formula (Vy)^2 = u^2 + 2gy given Vy, g and u. (It's a waterfall... so vertical velocity is assumably initially 0m/s)
Solve it for y. :}
 
Oh..

Hey thanks for your help man ... BUT ... i got it wrong ..andi failed ..
 

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