Help Need to calculate deceleration of object crashing

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SUMMARY

The discussion focuses on calculating the deceleration of a vehicle weighing 2935 lbs as it stops from speeds of 5 mph and 10 mph over a distance of less than 1 inch. The formula used is v² = 2ad, which allows for the calculation of deceleration (a) as a = v² / (2d). The conversion of speed from miles per hour to inches per second is also detailed, with 5 mph equating to 88 inches per second. The final calculation for deceleration from 5 mph is determined to be 220 mph/sec.

PREREQUISITES
  • Understanding of basic physics concepts, specifically kinematics.
  • Familiarity with the formula v² = 2ad for calculating deceleration.
  • Ability to convert units, particularly from miles per hour to inches per second.
  • Knowledge of how to interpret and manipulate equations in physics.
NEXT STEPS
  • Learn about unit conversions in physics, focusing on speed and acceleration.
  • Explore advanced kinematic equations for varying deceleration scenarios.
  • Research finite element analysis (FEA) applications in vehicle crash simulations.
  • Study the effects of weight and material properties on deceleration in impact scenarios.
USEFUL FOR

Engineers, physicists, and automotive safety analysts involved in vehicle dynamics and crash testing will benefit from this discussion.

tcdesignguy
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Hello,

Running a FEA on a object and need to calculate the deceleration from 5mph to 0mph and 10mph to 0mph . The vehicle weight is 2935lbs. They ran one test and said the vehicle stopped after it crumpled just less than 1". (I assume we can use the distance and velocities to solve the time?? (How long it took to stop from 5-0 in less than 1"))

So if i understand right we want to solve for t not a.

Thank you for your help!

-Steve Campbell
 
Last edited:
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Welcome to PF.

The formula to use is v^2 = 2 a d, where v is the speed, a is the deceleration, and d is the distance. Solving that for the deceleration a gives a = \frac{v^2}{2d}

You can https://www.google.com/#sclient=psy...,cf.osb&fp=7de1449e07857063&biw=1280&bih=607" to calculate the deceleration from that formula.

Or if you want to do things the hard way, then keep reading...

The units are tricky here! We have both miles and inches in the mixed in the mix, and I don't know what units you like to use for acceleration or deceleration -- I will use mph/sec as that seems convenient.

To make the units work out, first convert v into inches per second:
5 \ mi/hr \cdot \frac{12 \cdot 5280 \ inches}{1 \ mile}\cdot \frac{1 \ hr}{3600 \ sec}= \frac{5 \cdot 12 \cdot 5280}{3600} \frac{mi}{sec}= 88 \ in/sec

(Or https://www.google.com/#sclient=psy...,cf.osb&fp=7de1449e07857063&biw=1280&bih=607" to do the conversion for you.)

So the deceleration is a = \frac{v^2}{2d} = \frac{5 \ mph \cdot 88 \ in/sec}{2 \cdot 1 \ in} = 220 \ mph/sec
 
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