Help Needed: Explaining x^{x} = e^{xlgx} and x^{a}

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The equation x^{x} = e^{xlgx} can be understood through the properties of logarithms and exponentials, specifically that e^{ln(a)} = a. The expression x^{x} can be rewritten using the natural logarithm, leading to the equivalence with e^{xlgx}. Additionally, the same principles apply to x^{a}, where a is a constant, confirming that x^{a} can also be expressed in terms of e and logarithms. Understanding these relationships helps clarify the manipulation of exponential functions. Mastery of these concepts can alleviate the fear of working with e and exponentials.
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Hello,

I am having trouble getting my head around this:

Can someone explain why
x^{x} = e^{xlgx}

I cannot seem to understand why this is true. I am quite weak when it comes to handling exponentials. I dare say that I am terrified of e!

Also, would this also hold for a static power: so x^{a}

Thanks,

Luca
 
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Remember that for a > 0, \ln ( a^b ) = b \ln a and the fact that exponentation and the natural logarithm are inverse functions.
 
That makes sense!

Many thanks!
 
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