Help: Simple Algebra yet I fail

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The discussion focuses on transforming the first algebraic expression into the second, emphasizing the challenge of understanding the transformation process. Participants suggest adding terms like B*ln(f) to facilitate the transition and highlight the importance of logarithmic properties, specifically ln(a) - ln(b) = ln(a/b). They recommend expanding the brackets and manipulating the expressions to simplify the process. The conversation reflects a mix of frustration and encouragement, with an acknowledgment that the solution may not be straightforward. Overall, the participants aim to clarify the steps needed to achieve the transformation.
Curl
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How can I go from expression 1 to expression 2? Its easy to "show" they are equivalent, but if you started with 1, how will I get to 2? I got no clue how to transform it.



1
[ (A-B)*ln(c)+( B*ln(d)-A*ln(f) ) ] /ln(d/f)

2
(A-B)*ln(c/f)/ln(d/f)+B

I bet it's cake and I'm dumb.
 
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Hi Curl! :smile:

Add B*ln(f) - B*ln(f) to the top. :wink:
 
It is possible to show this, although it is not extremely easy.
One thing you do need is that
ln(a) - ln(b) = ln(a / b).

I suggest to start by opening up the "square" brackets.
You can also add 0, in the form (A - B) ln(f) - (A - B) ln(f) = A ln(f) - B ln(f) - (A - B) ln(f).
 
tiny-tim said:
Hi Curl! :smile:

Add B*ln(f) - B*ln(f) to the top. :wink:

haha, so I was right:

I bet it's cake and I'm dumb.
 

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