Help Solve PH Homework: NaOH + H20 at 25degrees

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To find the hydronium ion concentration ([H3O+]) in a solution of 0.535 g of NaOH in 100.0 mL of water at 25 degrees Celsius, one must first calculate the hydroxide ion concentration ([OH-]) from the dissociation of NaOH. The dissociation can be represented as NaOH → Na+ + OH-. After determining [OH-], the relationship pH + pOH = 14 can be used to find [H3O+]. The final answer for [H3O+] is 7.48 x 10^-14 M. Understanding the dissociation and proper balancing of the equation is crucial for solving similar problems.
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Homework Statement


We add 0.535 g of NaOH to 100.0 mL of water at 25degrees. What is [H3O+] in this solution at 25degrees?

hey guys, I've practiced these types of questions alot, but I've never came across one like this before. i tried writing equations and i got this 2NaOH+2H20>>2Na+2H30, but I am stuck at the next step. anyhelp would be good. thanks

ANSWER=7.48 x 10-14 M

(p.s) if anyone could sit down with me on msn or something for 20minutes I've got about 15 basic question i need help with (ive got the answers). thanks
 
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If that NaOH concentration is not too excessive for the model, you can try finding expected [OH-] and then use pH + pOH = 14
 
ta, could you help me write the equation then because i can't get it to balance good? tnaks
 
Your equation won't have H+ in it.

Check the page I have lined to. To start you have to calculate [OH-].
 
can i just write it like this..NaOH>Na+OH
 
Don't ignore charges, these are ions. But otherwise you are on the right track, this is just a simple dissociation.
 
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