Help Solve Twin Paradox Calc: A & B 1 Lyr Apart

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SUMMARY

The discussion focuses on calculating the time experienced by two observers, A and C, who are 1 light-year apart, with C traveling at 0.5 times the speed of light (0.5 C). When C synchronizes their watch with B, the time experienced by A and C can be determined using the formula for time dilation: ##\Delta\tau=\sqrt{\Delta t^2-\Delta x^2/c^2}##. The key variables include the distance ##\Delta x## and the velocity ##v## of C. By substituting these values, one can calculate the travel time ##\Delta t## as measured by stationary observers and subsequently deduce the elapsed time for the traveler, ##\Delta\tau##.

PREREQUISITES
  • Understanding of special relativity concepts, particularly time dilation.
  • Familiarity with the formula for time dilation: ##\Delta\tau=\sqrt{\Delta t^2-\Delta x^2/c^2}##.
  • Basic knowledge of the speed of light (c) and its significance in physics.
  • Ability to perform algebraic manipulations to solve for unknown variables.
NEXT STEPS
  • Study the implications of time dilation in special relativity.
  • Learn how to apply Lorentz transformations in different scenarios.
  • Explore practical examples of time dilation, such as GPS satellite technology.
  • Investigate the twin paradox and its resolutions in modern physics.
USEFUL FOR

Students of physics, educators teaching special relativity, and anyone interested in understanding the implications of relativistic travel on time perception.

almarino dtd
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A and B 1 lyr apart and sync watches, C moving at .5 C, when at B, C sync watch with B, what time does A and C's watch show when meet. (I was told answer already here but could not find).
 
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If an object travels a distance ##\Delta x## in a time ##\Delta t## then the time it experiences is ##\Delta\tau=\sqrt{\Delta t^2-\Delta x^2/c^2}##. You've specified ##\Delta x## and ##v##. Can you determine ##\Delta t##, the travel time as measured by the planets? If so, you should be able to deduce the elapsed time for the traveller, ##\Delta\tau##.
 

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