Help with a collisions question

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In a one-dimensional collision involving two blocks, one with a mass of 0.50 kg moving at 2.4 m/s and the other at rest with a mass of 0.80 kg, the introduction of a spring releasing 1.2 J of energy complicates the analysis. Momentum conservation applies to the total system, meaning the overall momentum remains constant despite the energy added by the spring. The kinetic energy after the collision must exceed the initial kinetic energy by 1.2 J, but this does not affect the conservation of momentum. The discussion emphasizes that while individual block momenta can change, the total momentum of the system is preserved. Understanding these principles is crucial for solving the velocities of both blocks post-collision.
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Two blocks can collide in a one-dimensional collision. The block on the left hass a mass of 0.50 kg and is initially moving to the right at 2.4 m/s toward a second block of mass 0.80 kg that is initially at rest. When the blocks collide, a cocked spring releases 1.2 J of energy into the system.
(a) What is the velocity of the first block after the collision?
(b) What is the velocity of the second block after the collision?

I don't know what to do. I assume equal momentum is given by the spring to each block, but i tried working out the momentum given to the system by pretending it was 1 big block and working out the KE and so the momentum. I though this was the momentum given to each block so worked out the velocity given to each block by the spring and adding it on to the two velocities i found using simultaneous equations of momentum and kinetic energy. It didn't work :(. I don't know what else to do without knowing how the energy is distributed between the two blocks.
 
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Hints:
(1) Is momentum conserved during the collision?
(2) How does the total kinetic energy after the collision compare to the total KE before the collision?

Translate your answers into equations and solve.
 
The kinetic energy after must be 1.2J greater than the kinetic energy before right? With the momentum equation, momentum can't be conserved if you release more energy into the system, because each block will have a greater momentum than they would have were the spring not there. Will overall momentum of the system be the same with or without the spring - do the extra momentums in opposite directions caused by the spring cancel?
 
joker_900 said:
The kinetic energy after must be 1.2J greater than the kinetic energy before right?
Right.
With the momentum equation, momentum can't be conserved if you release more energy into the system, because each block will have a greater momentum than they would have were the spring not there.
Conservation of momentum refers to the total momentum of the system, not the individual momenta of each block. And remember that momentum is a vector.
Will overall momentum of the system be the same with or without the spring - do the extra momentums in opposite directions caused by the spring cancel?
The total momentum of any system remains the same as long as no external forces act on it. (The spring is an internal force to the two-block system.)
 
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