Help with a proof with discrete dynamical sysmtes / chaos theory.

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SUMMARY

The discussion focuses on proving the occurrence of a period-doubling bifurcation for the function family Fλ(x) = λ(x³ - x) at the bifurcation point λ=1. Key points include identifying fixed points at 0, ±√2, and establishing the conditions for a unique fixed point pλ in the interval [λ0 - ε, λ0 + ε]. The user successfully derived the 2-cycle for Fλ and confirmed that as λ approaches λ0, the 2-cycle converges to the fixed point pλ0. The proof requires rigorous application of the chain rule along cycles and careful algebraic manipulation.

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  • Understanding of discrete dynamical systems and bifurcation theory
  • Familiarity with fixed points and cycles in dynamical systems
  • Proficiency in calculus, particularly the chain rule
  • Knowledge of algebraic manipulation and inequalities
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  • Study the concept of bifurcations in dynamical systems, focusing on period-doubling bifurcations
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Students and researchers in mathematics, particularly those studying dynamical systems, chaos theory, and bifurcation analysis. This discussion is beneficial for anyone seeking to understand the rigorous proof of bifurcations in iterative functions.

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Homework Statement


Consider the families of iterating functions Fλ(x) = λ(x3 - x). Fλ(x) undergoes a bifurcation at λ=1, about the fixed point x=0. Figure out what ilk of bifurcation is occurring for Fλ(x) and prove your assertion rigorously.

Homework Equations


My book says this about period-doubling bifurcations, and I need to prove all four of these to prove the problem.
Definition: A one-parameter family of functions Fλ undergoes a period-doubling bifurcation at the parameter value λ=λ0 if there is an open interval and an ε such that:
1. For each λ in the interval [λ0 - ε, λ0 + ε], there is a unique fixed point pλ for Fλ in I.
2.For λ0 - ε < λ < λ0, Fλ has no cycles of period 2 in I and pλ is attracting (resp. repelling).
3.For λ0 < λ < λ0 + ε, there is a unique 2-cycle q1λ,q2λ in I with Fλ(q1λ)=q2λ. This 2-cycle is attracting (resp. repelling). Meanwhile, the fixed point pλ is repelling (resp. attracting).
4.As λ -> λ0, we have qiλ -> pλ0
Also, these theorems are necessary (I think).
Chain Rule Along A Cycle: Suppose x0, x2, ..., xn-1 lie on a cycle of period n for F with xi = Fi(x0). Then
(Fn)'(x0) = F'(xn-1) * ... * F'(x1) * F'(x0).
The corollary for this is:
Suppose x0, x1, ..., xn-1 lie on an n-cycle for F. Then
(Fn)'(x0) = (Fn)'(x1) = ... = (Fn)'(xn-1)

The Attempt at a Solution

\
I have almost no idea where to start the proof. So far I have:
The interval I can = (-1, 1).

To answer 1., I know that there are fixed points at 0, +sqrt(2), -sqrt(2). So to have a unique fixed point pλ in the interval [λ0 - ε, λ0 + ε], 0<ε<sqrt(2). Can I just choose an arbitrary ε, like ε=1?

To answer 2., if ε=1, λ0 - ε < λ < λ0, so 0 - 1 < λ < 0, so -1<λ<0. I used algebra and got 2-cycles for x = -1, -.7548777, 0, 1 1.4655712, but all but x=1.4655712 lie in the interval I. Could someone check this? I may have made a mistake in my algebra. I don't see why else I would get this.

I really appreciate the help!
 
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I changed my interval I to (-.5, .5) so that part 2 would work.

And for part 3, I got this far.
Fλ(x)=λ(x3-x) is an odd function, so the second iteration of Fλ(x0) = x0. Using algebra I got x = (1 +- sqrt(1 - 4λ))/(2λ), so this is the 2-cycle for Fλ, but only for 0<λ<1/4.

For part 4, As λ -> λ0, we have qiλ -> pλ0. So substituting, I get as λ -> 0, qiλ -> 0.

Is everything right so far?
I'm not sure how to prove part 4.
 

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