Help with a question about collinear points

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Let P1, P2, ..., P5 be five points, no three of which are collinear. How many lines contain two of these five points?


How I thought about solving this was by way of combinations.

C5,2= (5*4*3*2)/2 = 60.


So there would be 60 lines that contain 2 of the 5 points. Is this a good way to approach this problem or is there a better way?

Thank you for your help!
 
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Welcome to PF!

Hi mathstudent88! Welcome to PF! :smile:

(hmm … 60 is a very large number … :rolleyes:)
mathstudent88 said:
Let P1, P2, ..., P5 be five points, no three of which are collinear. How many lines contain two of these five points?

How I thought about solving this was by way of combinations.

C5,2= (5*4*3*2)/2 = 60.

So there would be 60 lines that contain 2 of the 5 points. Is this a good way to approach this problem or is there a better way?

No … combinations is exactly the right way! :smile:

but … C5,2 = 5!/2!(5-2)! = … ? :wink:
 
haha I forgot all about the (5-2)! part... thank you for pointing it out for me!

the answer is 10.


Thanks again!
 
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