Help with a tug of war problem

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AI Thread Summary
In a two-dimensional tug-of-war problem, Alex, Betty, and Charles pull on a tire, which remains stationary despite their forces. Alex exerts a force of 211 N, and Charles exerts 181 N, but the direction of Charles's force is crucial for determining Betty's force. The first part of the problem was solved correctly, yielding Betty's force as 321.60 N when Charles pulls in a specific direction. However, confusion arises regarding the second scenario where Charles pulls in the opposite direction, which requires reevaluation of the force components. Clarification on how to approach the equilibrium conditions for this alternate direction is needed.
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Homework Statement


in a two-dimensional tug-of-war, Alex, Betty, and Charles pull horizontally on an automobile tire at the angles shown in the picture. The tire remains stationary in spite of the three pulls. Alex pulls with force of magnitude 211 N, and Charles pulls with force of magnitude 181 N. Note that the direction of is not given. What is the magnitude of Betty's force if Charles pulls in (a) the direction drawn in the picture or (b) the other possible direction for equilibrium?

** I got part a correct but i just do not understand what part b is looking for diagram link attached if doesn't work email.


http://i1148.photobucket.com/albums/o578/bettingw15/ScreenShot2012-06-04at95053AM.pn


Homework Equations


for part a i used Fb= -fa-Fc
found angle of fa = 180-42= 138
fby=-fay-fcy
fbsin(-90)=-fasin138-fcsintheta
then did same thing with x components to get angle theta= 29.97 then plugged that angle into formula -fb=-(211N0(sin138)-181N(sin 29.97)
= 321.60 N

I understand that but how do i do the other possible direction? The question does not even make sense to me


The Attempt at a Solution

 
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