Help with Algebra 2/Trigonometry problem

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The discussion focuses on the equation x = -b/2a, which represents the x-coordinate of the vertex of a parabola in the context of the quadratic formula. Participants clarify that this equation can be proven using calculus, as it indicates where the parabola reaches its minimum or maximum point. The vertical line at x = -b/2a serves as the axis of symmetry for the parabola. There is some confusion about the request for proof, with participants emphasizing the need for the specific problem context. Overall, the conversation highlights the importance of understanding how this equation relates to the properties of parabolas.
daodude1987
I'm having trouble with proving this equation: x=-b\2a
I am not really familiar with this equation but my trigonometry teacher says it is something from Algebra 2. How can I prove why or how this equation works for finding the x-coordinate?
 
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What do you mean "prove it"? It's an equation- its sometimes true and sometimes not. I suppose you mean "prove it is true for this particular situation" but you haven't told us what the situation is.
Could you please state the entire problem exactly?
 
Using simple calculus, you can show that x=-b/2a is the point at which a parabola attains a minimum or maximum.
The vertical line x=-b/2a that goes thru this point is the axis of symmetry.
 
Ah! Thanks, Stephen, I recognized "-b/(2a)" as part of the quadratic formula but didn't recognize that he was asking for a proof that the x coordinate of the vertex of the parabola y= ax2+ bx+ c is -b/(2a).
 
wait isn't -b/2a the vertex of a parabola? i kinda of forgot this but i think you can the coeficients of b and a get the vertex of the parabola
 
Yes, that was what StephenPrivitera told you!
 
o sorry i only saw the oroginal question
 

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