Help with applications of vector addition

AI Thread Summary
The discussion revolves around solving a physics problem involving vector addition and tension in a chain. A sign weighing 98N is suspended from a chain that is 4m long, with its ends attached to a ceiling 3m apart. The initial confusion arose from incorrectly calculating the angle between the chain and the ceiling, which was initially thought to be 97 degrees. After recalculating, the correct angle was found to be 41.41 degrees, leading to the correct tension formula. The user successfully determined the tension in the chains after identifying and correcting their mistake.
diana7
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I can't seem to draw this diagram.
A sign weighing 98N is suspended from the middle of a 4m long chain. The ends of the chain are attached to a ceiling at points 3m apart. Okay so i drew a diagram with a horizontal that is 3m and the chain hanging from each side is 2m long and the object is 98N. I'm not sure if its right because I'm not getting the answer that the textbook gives. And the question is to determine the tensions in the chains.
Your help is greatly appreciated.
 
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diana7 said:
I can't seem to draw this diagram.
A sign weighing 98N is suspended from the middle of a 4m long chain. The ends of the chain are attached to a ceiling at points 3m apart. Okay so i drew a diagram with a horizontal that is 3m and the chain hanging from each side is 2m long and the object is 98N. I'm not sure if its right because I'm not getting the answer that the textbook gives. And the question is to determine the tensions in the chains.
Your help is greatly appreciated.

What angle did you get between each part of the chain and the ceiling to which the two ends of the chain are attached?
 
I got 97 degrees, but it's not right. My friend told me that it is 41.41 degrees.
i did cosx = (2^2+2^2-3^2)/(2*2*2)
that I used the cos-1 to find the degree
 
I think i got it. i found my mistake! Thanks
 
diana7 said:
I think i got it. i found my mistake! Thanks

So you know how to do the whole thing now?
 
yupp. i had to divide 97.18 by 2 = 48.59
then I find hte angle since its a right angle triangle now. 90-48.59 = 41.41
then i know that the tension has to balance
so tsin41.41 + tsin41.41 = 98
2tsin41.41 = 98
t = 98 / (2sin41.41)
and i got the answer :) thanks for making me catch my mistake lol
 
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