Help with finding a transfer function

Click For Summary
SUMMARY

The discussion focuses on finding a transfer function for a circuit involving resistors and capacitors, specifically Resistor1 (47K ohm), capacitor1 (0.1 microfarad), and capacitor2 (0.002 microfarad). The objective is to add a resistor (R3) to achieve a flat high-frequency magnitude asymptote and to determine the minimum values of R1 and R2 to limit the phase lag between V2 and V1 to ±50 degrees. The participants discuss the process of simplifying the transfer function and plotting the Bode plot to visualize the magnitude and phase response.

PREREQUISITES
  • Understanding of transfer functions in electrical circuits
  • Familiarity with Bode plots and phase shift analysis
  • Knowledge of the quadratic formula for finding poles and zeros
  • Basic algebra skills for manipulating circuit equations
NEXT STEPS
  • Learn how to derive transfer functions for RLC circuits
  • Study Bode plot construction and interpretation techniques
  • Explore methods for calculating phase shifts in electrical circuits
  • Investigate the effects of component values on circuit behavior
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing and optimizing transfer functions in electronic circuits.

7emeraldempre
Messages
7
Reaction score
0

Homework Statement



---Resistor1=47K ohm----------------------------------------------
| | |
+ | | |
V1 capacitor1= .1micro farad | | +
- | c2=.002 micro Farad Load Resistor = 100K
| | | - R2= 1K | |
| | |
-----------------------------------------------------------------------


Add another resistance, R3 to the circuit so that the high-frequency magnitude asymptote
is flat instead of a ¡20dB=decade. Find the minimum values of R1 and R2 so that the
phase lag between V2 and V1 at any frequency does not exceed 50±. Write the new analytic
transfer function, H(s) = V2=V1, sketch the magnitude and phase of H(s) and label the
salient features.

I think if I add a resistor in series with c2 I will put the magnitude flat.


I figured an equation for this circuit (without the extra resistor) and the actual circuit is in the attachment. I could not copy and paste it into the window so I just put it into the attachment. I know that I am suppossed to be able to change the transfer funtion into a simplier form to get the poles and zeos but I get stumped there. I ask my professor but he said "that is what grading is for" and laughed. He's the type that gives students impossible problems and is amazed that we cannot do them right way. I like him and everything, just I do not flourish under his teaching style, other than that he is a good teacer.

I know this is an algebra problem but it would really help me out to see math and not just and answer.
 

Attachments

Physics news on Phys.org
Sorry, i did not know the circuit was going to come out that way, but what it is supposed to look like is in the attachment.
 
It looks like you got the rather complicated expression for the transfer function correct, but you made a mistake somewhere when you tried to simplify it.

See the first attached image showing the correct simplified expression, and also the expression for the case where an additional resistor, R3, is in series with C2.

The second image shows the log magnitude and phase of the transfer function. I've got a value of R3=1000 there, but it's not used in this plot.

The third image shows the same for the case of R3=30 ohms in series with C2.

The transfer function denominator only involves the variable s to the second power, so you can use the quadratic formula to determine the poles of the denominator, which are the zeros of the transfer function. The poles of the numerator are obvious by inspection. Knowing the poles and zeros, you can plot the asymptotic response (the Bode plot).

I don't understand the bit about the phase lag limits being 50+-, since the phase shift only goes negative. I suppose one way to get the values of R1 and R2 for some specified phase shift would be to manually tweak the values and repeatedly plot phase shift.

But, if your instructor wants precise values, you're going to have to differentiate the expression for phase shift, find the two frequencies of maximum negative phase shift and using those expressions, set them both equal to 50 degrees (or whatever your instructor wants), and solve for R1 and R2.
 

Attachments

  • Xfer1.png
    Xfer1.png
    13.1 KB · Views: 607
  • Xfer2.png
    Xfer2.png
    20.2 KB · Views: 605
  • Xfer3.png
    Xfer3.png
    26.4 KB · Views: 606
Last edited:

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 10 ·
Replies
10
Views
6K