- #1
HelpPlease92
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Hello everyone.
In Physics class, we did a lab where we dropped golf balls into a box of sand from a height of 9 ft (or 2.743 meters). The golf ball had a mass of .046 kg. We were not allowed to time the drop so these were the only givens. We also measured the depth of the "crater" the golf ball made in the sand. The depth was .0174 meters.
The first question asked for the acceleration of the ball while slowing down in the sand.
The second asked for the time to stop in the sand.
The third asked for the impulse the sand applied to the golf ball.
For the first question, I used the equation [itex]v=\sqrt{2gh}[/itex] to find the final velocity of the ball. Plugging in the number 2.743 m for h, I got about 7.34 m/s for vf.
I then used the equation vf2= vi2 + 2aΔx to find the acceleration. I assumed, since the ball was dropped, the golf ball had an initial velocity of 0 m/s. I used 2.743 m + depth for Δx.
After plugging in everything and solving, I found the acceleration to be 9.75 m/s2
I then used the acceleration to solve for time:
a= [itex]\frac{Δv}{Δt}[/itex].
I found t to be .75215 seconds.
For Impulse, I used the equation I=FΔt, and since ƩF=ma, I solved for F, which was about .449 Newtons, and got impulse to be .337 Ns upward (since it asked the impulse the sand applied to the ball).
Then it asked another question relating to the lab:
Assuming a refrigerator-sized meteorite (100 kg) strikes a sand desert on the Earth at a terminal velocity of 300 m/s, predict the crater's depth based on data gathered in this lab.
I feel like there's not enough information to solve this problem. Is there something I'm missing?
I first found the Impulse by multiplying the terminal velocity with the mass (would it be right to assume that the meteorite started at rest?). The impulse I calculated came out to be 30000 Ns.
I used [itex]v=\sqrt{2gh}[/itex] again to find the h, and it came out to be 4587.16 m but I'm clueless as what to do next.
I really appreciate anyone's help--it's been giving me a lot of trouble.
Thank you.
In Physics class, we did a lab where we dropped golf balls into a box of sand from a height of 9 ft (or 2.743 meters). The golf ball had a mass of .046 kg. We were not allowed to time the drop so these were the only givens. We also measured the depth of the "crater" the golf ball made in the sand. The depth was .0174 meters.
The first question asked for the acceleration of the ball while slowing down in the sand.
The second asked for the time to stop in the sand.
The third asked for the impulse the sand applied to the golf ball.
For the first question, I used the equation [itex]v=\sqrt{2gh}[/itex] to find the final velocity of the ball. Plugging in the number 2.743 m for h, I got about 7.34 m/s for vf.
I then used the equation vf2= vi2 + 2aΔx to find the acceleration. I assumed, since the ball was dropped, the golf ball had an initial velocity of 0 m/s. I used 2.743 m + depth for Δx.
After plugging in everything and solving, I found the acceleration to be 9.75 m/s2
I then used the acceleration to solve for time:
a= [itex]\frac{Δv}{Δt}[/itex].
I found t to be .75215 seconds.
For Impulse, I used the equation I=FΔt, and since ƩF=ma, I solved for F, which was about .449 Newtons, and got impulse to be .337 Ns upward (since it asked the impulse the sand applied to the ball).
Then it asked another question relating to the lab:
Assuming a refrigerator-sized meteorite (100 kg) strikes a sand desert on the Earth at a terminal velocity of 300 m/s, predict the crater's depth based on data gathered in this lab.
I feel like there's not enough information to solve this problem. Is there something I'm missing?
I first found the Impulse by multiplying the terminal velocity with the mass (would it be right to assume that the meteorite started at rest?). The impulse I calculated came out to be 30000 Ns.
I used [itex]v=\sqrt{2gh}[/itex] again to find the h, and it came out to be 4587.16 m but I'm clueless as what to do next.
I really appreciate anyone's help--it's been giving me a lot of trouble.
Thank you.