Help with Rotating Weighted Ball in Socket: Design Rules Needed

AI Thread Summary
A ball with a bias weight at a point on its circumference, when placed in a slightly larger socket, will experience unique movement dynamics. The asymmetrical contact between the ball and the socket leads to a stable position where the weighted point seeks to align closest to the center of the Earth. As the socket rotates, the ball will initially move with the socket due to friction, but it will quickly revert to its stable orientation, resisting further movement. This behavior is influenced by factors such as friction and the gravitational pull on the biased weight, which creates resistance to displacement. Understanding these principles is crucial for design considerations involving biased weighted balls in sockets.
john winslow
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Please can you help with the following.

If a ball which is bias weighted at a point on its circumference is enclosed in a socket which is few thousandths of an inch bigger in diameter than the ball will the weighted bias cause the ball to rotate as the socket is turned in the opposite direction or will the ball simply turn with the rotation of the socket in the same direction. I guess it has a lot to do with friction, weight bias etc. Can anyone help with any design rules for this.
Many thanks in advance.
John
 
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Originally posted by john winslow
Please can you help with the following.

If a ball which is bias weighted at a point on its circumference is enclosed in a socket which is few thousandths of an inch bigger in diameter than the ball will the weighted bias cause the ball to rotate as the socket is turned in the opposite direction or will the ball simply turn with the rotation of the socket in the same direction. I guess it has a lot to do with friction, weight bias etc. Can anyone help with any design rules for this.
Many thanks in advance.
John

The circumferential bias weight of the ball will cause that ball to be in asymetric contact with the spherical container. Also, The bias weight will tend towards a stable position such that it is the closest point on the ball to the center of the earth.
That point of contact will have the greatest resitance to movement, as it will have 1) the most contact with the container, and 2) will "fight" displacement due to its gravitational attraction towards the center of the earth.
Given such, what will happen is that a turn of the container will cause the ball to turn with it for a very short distance due to friction, and then the ball will rotate back to its "stable" orientation.
 
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