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## Homework Statement

We need to solve the double integral:

6 -2/3x+4

∫ ∫ [12-2x-(3y/4)] dy dx

0 0

## Homework Equations

(a+b)

^{2}= a

^{2}+ 2ab + b

^{2}

## The Attempt at a Solution

I've got to:

6

(1/4) ∫ [12y-2xy-(3y

^{2}/2)] evaluated at -2/3x + 4 and 0.

0

6

(1/4) ∫ [12(-2/3x + 4) - 2x(-2/3x + 4) - (3(-2/3x + 4)

^{2}/2)]

0

This is where I'm stuck. I could solve the rest of the integral if I could simplify this right. Sometimes, I think simplifying the integral is harder than the integration itself.