# Help with simplifying integral

## Homework Statement

We need to solve the double integral:

6 -2/3x+4
∫ ∫ [12-2x-(3y/4)] dy dx
0 0

## Homework Equations

(a+b)2 = a2 + 2ab + b2

## The Attempt at a Solution

I've got to:

6
(1/4) ∫ [12y-2xy-(3y2/2)] evaluated at -2/3x + 4 and 0.
0
6
(1/4) ∫ [12(-2/3x + 4) - 2x(-2/3x + 4) - (3(-2/3x + 4)2/2)]
0

This is where I'm stuck. I could solve the rest of the integral if I could simplify this right. Sometimes, I think simplifying the integral is harder than the integration itself.